The area of a rectangle is thrice that of a square. The length of the rectangle is 40 cm and the breadth of the rectangle is (3/2) times of the square. The side of the square in cm is__________?
A. 15
B. 20
C. 30
D. 60
A. 15
B. 20
C. 30
D. 60
A. 15m
B. 4m
C. 3m
D. None of these
Explanation:
Breadth = x meters
Length = ( 4/3 x) m
X × 4/3 x = 300 or x2 = 300 × 3/4 = 225 or x =15
Hence, [(Length) – (breadth)] = ( 4/3 x-x) = 1/3
x => ( 1/3×15) m = 5 m
A. 125
B. 156.25
C. 50
D. 56.25
A. 260m
B. 280m
C. 360m
D. None of these
Explanation:
5x – 4x = 20 or x = 20
Length = (5 x 20) m = 100 m
Breadth = (4 x 20) = 80 m
Perimeter = 2(100+80) = 360 m
A. 50m
B. 100m
C. 150m
D. 200m
Explanation:
Let length = 5x meters and breadth = 3x meters
Perimeter = 2 x (5x + 3x) m = 16x metres.
Perimeter = Total cost/Rate = (3000/7.50) m = 400 m.
16x = 400 or x = 25
(Length) – (breadth) = (5 x 25 – 3 x 25)m
= (2 x 25) = 50 m
A. 37
B. 38
C. 39
D. 40
Explanation:
Perimeter = 2×(36+21) m = 114 m
Number of flag staffs = (114/3) = 38
A. 20
B. 30
C. 60
D. None of these
Explanation:
Area of the plot = (3×1200)Sq.m = 3600 Sq.m
Breadth = x meters and length = 4x meters
4x × x = 3600 or x2 = 900 0r x = 30
Length of plot = 4x = (4×30) m = 120 m
A. 15.12 sq.cm
B. 13.52 sq.cm
C. 12.62 sq.cm
D. 10 sq.cm
A. 24/5 cm
B. 12/5 cm
C. 7/5 cm
D. None of these
A. 160m × 27m
B. 240m × 18m
C. 120m × 36m
D. 135m × 32m
Let the side of smaller square at the extreme right be a
Then side of the larger square is 3a
Total area of the field = a2 + a2 +a2 + (3a)2 +(3a)2 = 30a2
Therefore, 30 a2 = 4320 => a2 = 432 / 3 = 144 => a = 12
Smaller side of the field = 36
Larger side of the field = (3a) × 3 + a = 10 a = 10 × 12 = 120
Original Dimensions of the field = 120m × 36m