A trader owes a merchant Rs. 10,028 due 1 year hence. The trader wants to settle the account after 3 months. If the rate of interest 12% per annum, how much cash should he pay?
A. Rs. 9025.20
B. Rs. 9200
C. Rs. 9600
D. Rs. 9560
A. Rs. 9025.20
B. Rs. 9200
C. Rs. 9600
D. Rs. 9560
A. Rs. 992
B. Rs. 1112
C. Rs. 1056
D. Rs. 1182
Principal = 800 SI = 120 Time = 3 year
Rate = (100*120/800*3) = 5%
New rate = 8 % principal = 800 time 3 year
SI = (800*8*3/100) = 192
New amount = 800 + 192= 992
A. Rs.750
B. Rs.700
C. Rs.940
D. Rs.820
A. Rs.3100
B. Rs.2700
C. Rs.2200
D. Rs.1800
Let the man invests Rs.x at 6% and Rs.y at 7%
Simple Interest on Rs.x at 6% for 2 years + Simple Interest on Rs.y at 7% for 2 years = Rs.354
x×6×2/100+y×7×2/
A. 6%
B. 5%
C. 7%
D. 8%
1. To find the interest, subtract the principal from the balance.
$618 – $600 = $18
2.Use the simple interest formula and solve for r.
I = Prt
18= 600 x r x (1/2)
r= 0.06 =6%
A. 65 years
B. 56 years
C. 45 years
D. 57 years
Simple interest is given by the formula SI = (pnr/100), where p is the principal, n is the numberof years for which it is invested, r is the rate of interest per annum
In this case, Rs. 1250 has become Rs.10,000.
Therefore, the interest earned = 10,000 – 1250 = 8750.
8750 = [(1250 x n x 12.5)/100]
=> n = 700 / 12.5 = 56 years.
A. 11/3%
B. 14/3%
C. 12%
D. 14%
What is the rate of interest at which Rs.150 becomes Rs. 220 in 10 years. Read More »
interest Mcqs, Mathematics Mcqs A. Rs. 700
B. Rs. 690
C. Rs. 650
D. Rs. 698
Simple Interest (SI) for 1 year = 854-815 = 39
Simple Interest (SI) for 3 years = 39 × 3 = 117
Principal = 815 – 117 = Rs.698
A. Rs.4000
B. Rs.9000
C. Rs.5000
D. Rs.6000
Let sum = P and original rate = R. Then
[(P * (R+2) * 3)/100] – [ (P * R * 3)/100] = 360
3P*(R+2) – 3PR = 36000
3PR + 6P – 3PR = 36000
6P = 36000
P = 6000
A. 5%
B. 8%
C. 12%
D. 15%
S.I. for 3 years = Rs. (12005 – 9800) = Rs. 2205.
S.I. for 5 years = Rs.[ (2205/3) x 5 ] = Rs.3675
Principle = Rs.(9800-3675) = Rs.6125
Rate=12%