A B C D + AB C D =
Question: A B C D + AB C D =
[A].ABC
ABCD
A B D
ABCD
[A].
[B].
[C].
[D].
Answer: Option C
Explanation:
A B C D + A B C D = A B D(C + C) = A B D .
Electronics And Communication Engineering
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A coil of resistance R and inductance L is connected in series with 5 μF capacitor. The source frequency is equal to resonance frequency and circuit current is 0.5 A. Another 5 F capacitor is connected in parallel with the above capacitor. The circuit current will be
Question: A coil of resistance R and inductance L is connected in series with 5 μF capacitor. The source frequency is equal to resonance frequency and circuit current is 0.5 A. Another 5 F capacitor is connected in parallel with the above capacitor. The circuit current will be
[A].0.5 A [B].
more than 0.5 A [C].
less than 0.5 A [D].
0.5 A or less Answer: Option C
Explanation:
Since C increases, the circuit will not be in resonance. Therefore, current decreases (In series resonant circuit current is maximum at resonance).
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A full wave rectifier using centre tapped transformer and a bridge rectifier use similar diodes and have equal no load output voltage. Under equal load conditions
Question: A full wave rectifier using centre tapped transformer and a bridge rectifier use similar diodes and have equal no load output voltage. Under equal load conditions
[A].Output voltage of bridge rectifier [B].
Output voltage of bridge rectifier will be more than that of other [C].
Output voltage of both will be exactly equal [D].
Output voltage of any one may be more than that of other Answer: Option A
Explanation:
Since two diodes are in series bridge rectifier, voltage drop is more.
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In the given figure, A = B = 1 and C = D = 0. Then Y =
Question: In the given figure, A = B = 1 and C = D = 0. Then Y =
[A].1 [B].
0 [C].
either 1 or 0 [D].
indeterminate Answer: Option B
Explanation:
The CD inputs when fed to NOR gate give output 1. Therefore Y = 1.1.1 = 0.
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A coil of resistance R and inductance L is connected in series with 10 mF capacitor. The resonant frequency is 1000 Hz. Another 10 F capacitor is connected in parallel with the above capacitor. The new resonance frequency will be
Question: A coil of resistance R and inductance L is connected in series with 10 mF capacitor. The resonant frequency is 1000 Hz. Another 10 F capacitor is connected in parallel with the above capacitor. The new resonance frequency will be
[A].1000 Hz [B].
more than 1000 Hz [C].
less than 1000 Hz [D].
may be more or less than 10000 Hz Answer: Option C
Explanation:
Total capacitance increases and therefore ωr decreases.
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A series resonant circuit has inductance L. If L is increased, the resonant frequency
Question: A series resonant circuit has inductance L. If L is increased, the resonant frequency
[A].increases [B].
decreases [C].
remains constant [D].
may increases or decreases Answer: Option B
Explanation:
. As L increases ωr decreases.
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As compared to full wave rectifier, a half wave rectifier
Question: As compared to full wave rectifier, a half wave rectifier
[A].has higher ripple factor [B].
has lower ripple factor [C].
may have higher or lower ripple factor [D].
has same ripple factor Answer: Option A
Explanation:
No answer description available for this question.
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Four inputs A, B, C, D are fed to a NOR gate. The output of NOR gate is fed to an inverter. The output of inverter is
Question: Four inputs A, B, C, D are fed to a NOR gate. The output of NOR gate is fed to an inverter. The output of inverter is
[A].A + B + C + D [B].
A + B + C + D [C].
ABCD [D].
ABCD Answer: Option A
Explanation:
Output = = A + B + C + D.
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Consider a 565 PLL with RT = 10 kΩ and CT = 0.01 μF. What is the output frequency of the VCO?
Question: Consider a 565 PLL with RT = 10 kΩ and CT = 0.01 μF. What is the output frequency of the VCO?
[A].10 kHz [B].
5 kHz [C].
2.5 kHz [D].
1.25 kHz Answer: Option A
Explanation:
No answer description available for this question.
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A series resonant circuit has R = 10 Ω, L = 1 μH and C = 1 mF. If R is increased to 20 Ω the resonant frequency
Question: A series resonant circuit has R = 10 Ω, L = 1 μH and C = 1 mF. If R is increased to 20 Ω the resonant frequency
[A].increases [B].
decreases [C].
remains constant [D].
may increases or decreases Answer: Option C
Explanation:
fr depends only on L and C.