A B C D + AB C D =
[A].
[B].
[C].
[D].
Answer: Option C
Explanation:
A B C D + A B C D = A B D(C + C) = A B D .
A B C D + AB C D = Read More »
Digital Electronics, Electronics And Communication Engineering[B].
[C].
[D].
Answer: Option C
Explanation:
A B C D + A B C D = A B D(C + C) = A B D .
A B C D + AB C D = Read More »
Digital Electronics, Electronics And Communication Engineering[B].
[C].
[D].
Answer: Option C
Explanation:
Since C increases, the circuit will not be in resonance. Therefore, current decreases (In series resonant circuit current is maximum at resonance).
[B].
[C].
[D].
Answer: Option A
Explanation:
Since two diodes are in series bridge rectifier, voltage drop is more.
[B].
[C].
[D].
Answer: Option B
Explanation:
The CD inputs when fed to NOR gate give output 1. Therefore Y = 1.1.1 = 0.
In the given figure, A = B = 1 and C = D = 0. Then Y = Read More »
Digital Electronics, Electronics And Communication Engineering[B].
[C].
[D].
Answer: Option C
Explanation:
Total capacitance increases and therefore ωr decreases.
[B].
[C].
[D].
Answer: Option B
Explanation:
. As L increases ωr decreases.
A series resonant circuit has inductance L. If L is increased, the resonant frequency Read More »
Electronics And Communication Engineering, Networks Analysis And Synthesis[B].
[C].
[D].
Answer: Option A
Explanation:
No answer description available for this question.
As compared to full wave rectifier, a half wave rectifier Read More »
Analog Electronics, Electronics And Communication Engineering[B].
[C].
[D].
Answer: Option A
Explanation:
Output = = A + B + C + D.
[B].
[C].
[D].
Answer: Option A
Explanation:
No answer description available for this question.
[B].
[C].
[D].
Answer: Option C
Explanation:
fr depends only on L and C.