A Hartley oscillator uses
[A].
[B].
[C].
[D].
Answer: Option A
Explanation:
No answer description available for this question.
A Hartley oscillator uses Read More »
Analog Electronics, Electronics And Communication Engineering[B].
[C].
[D].
Answer: Option A
Explanation:
No answer description available for this question.
A Hartley oscillator uses Read More »
Analog Electronics, Electronics And Communication Engineering[B].
[C].
[D].
Answer: Option A
Explanation:
No answer description available for this question.
In a three variable K map four adjacent cells give Read More »
Digital Electronics, Electronics And Communication Engineering[B].
[C].
[D].
Answer: Option B
Explanation:
It has R and L in one branch and a variable capacitance in second branch.
[B].
[C].
[D].
Answer: Option C
Explanation:
New lower cutoff frequency = .
[B].
[C].
[D].
Answer: Option A
Explanation:
No answer description available for this question.
In a four variable K map eight adjacent cells give Read More »
Digital Electronics, Electronics And Communication Engineering[B].
[C].
[D].
Answer: Option C
Explanation:
As R increases, Q decreases, bandwidth = . Therefore, bandwidth increases. Hence lower half power frequency will be less than ωr.
[B].
[C].
[D].
Answer: Option B
Explanation:
The circuit will not in resonance. In parallel resonant circuit the current is minimum at resonance. Therefore, current will increase.
[B].
[C].
[D].
Answer: Option A
Explanation:
A + B + C = 000 = M0 .
Maxterm designation for A + B + C is Read More »
Digital Electronics, Electronics And Communication Engineering[B].
[C].
[D].
Answer: Option D
Explanation:
No answer description available for this question.
[B].
[C].
[D].
Answer: Option C
Explanation:
No answer description available for this question.