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Digital Electronics

Converting the Boolean expression LM + M(NO + PQ) to SOP form, we get ________.

Question: Converting the Boolean expression LM + M(NO + PQ) to SOP form, we get ________.
[A].

LM + MNOPQ

[B].

L + MNO + MPQ

[C].

LM + M + NO + MPQ

[D].

LM + MNO + MPQ

Answer: Option D

Explanation:

No answer description available for this question.

Converting the Boolean expression LM + M(NO + PQ) to SOP form, we get ________. Read More »

Boolean Algebra And Logic Simplification, Digital Electronics

Inputs A and B of the given figure are applied to a NAND gate. The output is LOW

Question: Inputs A and B of the given figure are applied to a NAND gate. The output is LOW
[A].

from 0 to 6

[B].

from 0 to 2

[C].

from 0 to 1 and 2 to 3

[D].

from 1 to 2 and 3 to 4

Answer: Option C

Explanation:

NAND gate gives Low output if all inputs are High. For other combinations of inputs, output is High.

Inputs A and B of the given figure are applied to a NAND gate. The output is LOW Read More »

Digital Electronics, Electronics And Communication Engineering

For the given truth table, the correct Boolean expression is

Question: For the given truth table, the correct Boolean expression is
[A].

XYZ + X YZ + X Y Z

[B].

X Y Z + XYZ + X YZ

[C].

X Y Z + XYZ + XY Z

[D].

XYZ + XYZ + XY Z

Answer: Option B

Explanation:

No answer description available for this question.

For the given truth table, the correct Boolean expression is Read More »

Digital Electronics, Electronics And Communication Engineering