Arithmetic Reasoning

Question: After distributing the sweets equally among 25 children, 8 sweets remain. Had the number of children been 28, 22 sweets would have been left after equal distribution. What was the total number of sweets ?
[A].

328

[B].

348

[C].

358

[D].

Data inadequate

Answer: Option C

Explanation:

Let the total number of sweets be (25x + 8).

Then, (25x + 8) – 22 is divisible by 28

(25x – 14) is divisible by 28 28x – (3x + 14) is divisible by 28

(3x + 14) is divisible by 28 x = 14.

Therefore Total number of sweets = (25 x 14 + 8) = 358.

Question: A number of friends decided to go on a picnic and planned to spend Rs. 96 on eatables. Four of them, however, did not turn up. As a consequence, the remaining ones had to contribute Rs. 4 each extra. The number of those who attended the picnic was
[A].

8

[B].

12

[C].

16

[D].

24

Answer: Option A

Explanation:

Question: On Children’s Day, sweets were to be equally distributed among 175 children in a school. Actually on the Children’s Day, 35 children were absent and therefore each child got 4 sweets extra. Total how many sweets were available for distribution ?
[A].

2400

[B].

2480

[C].

2680

[D].

2800

Answer: Option D

Explanation:

Question: A man has Rs. 480 in the denominations of one-rupee notes, five-rupee notes and ten-rupee notes. The number of notes of each denomination is equal. What is the total number of notes that he has ?
[A].

45

[B].

60

[C].

75

[D].

90

Answer: Option D

Explanation:

Let number of notes of each denomination be x.

Then, x + 5x + 10x = 480 16x = 480 x = 30.

Hence, total number of notes = 3x = 90.

Question: A total of 324 coins of 20 paise and 25 paise make a sum of Rs. 71. The number of 25-paise coins is
[A].

120

[B].

124

[C].

144

[D].

200

Answer: Option B

Explanation:

Let the number of 20-paise coins be x. Then, number of 25-paise coins = (324 – x).

Therefore 0.20 x x + 0.25 (324 – x) = 71 20x + 25 (324 – x) = 7100

5x= 1000 x = 200. Hence, number of 25-paise coins = (324 – x) – 124.

Question: In three coloured boxes – Red, Green and Blue, 108 balls are placed. There are twice as many balls in the green and red boxes combined as there are in the blue box and twice as many in the blue box as there are in the red box. How many balls are there in the green box ?
[A].

18

[B].

36

[C].

45

[D].

None of these

Answer: Option D

Explanation:

Let R, G and B represent the number of balls in red, green and blue boxes respectively.

Then, .

R + G + B = 108 …(i),

G + R = 2B …(ii)

B = 2R …(iii)

From (ii) and (iii), we have G + R = 2x 2R = 4R or G = 3R.

Putting G = 3R and B = 2R in (i), we get:

R + 3R + 2R = 108 6R = 108 R = 18.

Therefore Number of balls in green box = G = 3R = (3 x 18) = 54.

Question: If 100 cats kill 100 mice in 100 days, then 4 cats would kill 4 mice in how many days ?
[A].

1 day

[B].

4 days

[C].

40 days

[D].

100 days

Answer: Option D

Explanation:

Question: If a clock takes seven seconds to strike seven, how long will it take to strike ten ?
[A].

7 seconds

[B].

9 seconds

[C].

10 seconds

[D].

None of these

Answer: Option D

Explanation:

Question: A tailor had a number of shirt pieces to cut from a roll of fabric. He cut each roll of equal length into 10 pieces. He cut at the rate of 45 cuts a minute. How many rolls would be cut in 24 minutes ?
[A].

32 rolls

[B].

54 rolls

[C].

108 rolls

[D].

120 rolls

Answer: Option D

Explanation:

Number of cuts made to cut a roll into 10 pieces = 9.

Therefore Required number of rolls = (45 x 24)/9 = 120.

Question: A number consists of two digits whose sum is 11. If 27 is added to the number, then the digits change their places. What is the number ?
[A].

47

[B].

65

[C].

83

[D].

92

Answer: Option A

Explanation:

Let the ten’s digit be x. Then, unit’s digit = (11 – x).

So, number = 10x + (11 – x) = 9x + 11.

Therefore (9x + 11) + 27 = 10 (11 – x) + x 9x + 38 = 110 – 9x 18x = 72 x = 4.

Thus, ten’s digit = 4 and unit’s digit = 7.

Hence, required number = 47.