A. 20
B. 30
C. 60
D. None of these
Explanation:
Area of the plot = (3×1200)Sq.m = 3600 Sq.m
Breadth = x meters and length = 4x meters
4x × x = 3600 or x2 = 900 0r x = 30
Length of plot = 4x = (4×30) m = 120 m
		A. 20
B. 30
C. 60
D. None of these
Explanation:
Area of the plot = (3×1200)Sq.m = 3600 Sq.m
Breadth = x meters and length = 4x meters
4x × x = 3600 or x2 = 900 0r x = 30
Length of plot = 4x = (4×30) m = 120 m
		A. 15.12 sq.cm
B. 13.52 sq.cm
C. 12.62 sq.cm
D. 10 sq.cm
		A. 24/5 cm
B. 12/5 cm
C. 7/5 cm
D. None of these
		A. 160m × 27m
B. 240m × 18m
C. 120m × 36m
D. 135m × 32m
Let the side of smaller square at the extreme right be a
Then side of the larger square is 3a
Total area of the field = a2 + a2 +a2 + (3a)2 +(3a)2 = 30a2
Therefore, 30 a2 = 4320 => a2 = 432 / 3 = 144 => a = 12
Smaller side of the field = 36
Larger side of the field = (3a) × 3 + a = 10 a = 10 × 12 = 120
Original Dimensions of the field = 120m × 36m
		A. A square with an area of 36 sq.cm
B. An Equilateral Triangle with a side of 9 cm
C. A rectangle with 10 cm as length and 40 sq.cm as area
D. A circle with a radius of 4 cm
Explanation:
From Option (A), Area of Square = 36 Sq.cm
Therefore, Side of Square = √36 = 6 cm And
Perimeter of square = 4 × 6 = 24 cm
From option (B), Side of an Equilateral Triangle = 9 cm
Therefore, Perimeter of triangle = 3 × 9 = 27 cm
From Option (C), Length of rectangle , l= 10 cm And
Area of Rectangle = 40 Sq.cm
Let Breadth of Rectangle, b = 40/10 = 4 cm
Therefore, Perimeter of rectangle = 2(10 + 4) = 28 cm
From Option (D), Radius of Circle = 4 cm
Therefore Circumference of circle = 2 × 3.14 × 4 = 25.12 cm
So, Rectangle with 10 cm as length and 40 Sq.cm as an area has a greater perimeter than the rest.
		A. 26.4 m2
B. 39.6 m2
C. 52.8 m2
D. 79.2 m2
		A. 0.35 cm2
B. 17.5 cm2
C. 8.75 cm2
D. 55 cm2
		A. (400 – 100π) cm2</sup
B. (400 – 2π) cm2</sup
C. (400 – 200π) cm2</sup
D. 200π cm2</sup
		A. Rs.45
B. Rs.78
C. Rs.44
D. Rs.40
π (152 – 132) = 176
176 * 1/4 = Rs.44
		A. 25 cm
B. 28 cm
C. 30 cm
D. 35 cm