Aptitude

Question:
If a person walks at 14 km/hr instead of 10 km/hr, he would have walked 20 km more. The actual distance travelled by him is:

[A].

50 km

[B].

56 km

[C].

70 km

[D].

80 km

Answer: Option A

Explanation:

Let the actual distance travelled be x km.

Then,	x	=	x + 20
	10		14

14x = 10x + 200

4x = 200

x = 50 km.

Question:
In covering a distance of 30 km, Abhay takes 2 hours more than Sameer. If Abhay doubles his speed, then he would take 1 hour less than Sameer. Abhay’s speed is:

[A].

5 kmph

[B].

6 kmph

[C].

6.25 kmph

[D].

7.5 kmph

Answer: Option A

Explanation:

Let Abhay’s speed be x km/hr.

Then,	30	–	30	= 3
	x		2x

6x = 30

x = 5 km/hr.

Question:
A train can travel 50% faster than a car. Both start from point A at the same time and reach point B 75 kms away from A at the same time. On the way, however, the train lost about 12.5 minutes while stopping at the stations. The speed of the car is:

[A].

100 kmph

[B].

110 kmph

[C].

120 kmph

[D].

130 kmph

Answer: Option C

Explanation:

Let speed of the car be x kmph.

Then, speed of the train =	150	x	=		3	x	kmph.
	100				2

	75	–	75	=	125
	x		(3/2)x		10 x 60

	75	–	50	=	5
	x		x		24

x =		25 x24		= 120 kmph.
		5

Question:
A man covered a certain distance at some speed. Had he moved 3 kmph faster, he would have taken 40 minutes less. If he had moved 2 kmph slower, he would have taken 40 minutes more. The distance (in km) is:

[A].

35

[B].

36	2
	3

[C].

37	1
	2

[D].

40

Answer: Option D

Explanation:

Let distance = x km and usual rate = y kmph.

Then,	x	–	x	=	40	2y(y + 3) = 9x ….(i)
	y		y + 3		60

And,	x	–	x	=	40	y(y – 2) = 3x ….(ii)
	y -2		y		60

On dividing (i) by (ii), we get: x = 40.

Question: Robert is travelling on his cycle and has calculated to reach point A at 2 P.M. if he travels at 10 kmph, he will reach there at 12 noon if he travels at 15 kmph. At what speed must he travel to reach A at 1 P.M.?

[A].

8 kmph

[B].

11 kmph

[C].

12 kmph

[D].

14 kmph

Answer: Option C

Explanation:

Let the distance travelled by x km.

Then,	x	–	x	= 2
	10		15

3x – 2x = 60

x = 60 km.

Time taken to travel 60 km at 10 km/hr =		60	hrs	= 6 hrs.
		10

So, Robert started 6 hours before 2 P.M. i.e., at 8 A.M.

Required speed =		60	kmph.	= 12 kmph.
		5

Question:
A car travelling with of its actual speed covers 42 km in 1 hr 40 min 48 sec. Find the actual speed of the car.

[A].

17	6	km/hr
	7

[B].

25 km/hr

[C].

30 km/hr

[D].

35 km/hr

Answer: Option D

Explanation:

Time taken = 1 hr 40 min 48 sec = 1 hr 40	4	min = 1	51	hrs =	126	hrs.
	5		75		75

Let the actual speed be x km/hr.

Then,	5	x x	126	= 42
	7		75

x =		42 x 7 x 75		= 35 km/hr.
		5 x 126

Question: A man on tour travels first 160 km at 64 km/hr and the next 160 km at 80 km/hr. The average speed for the first 320 km of the tour is:

[A].

35.55 km/hr

[B].

36 km/hr

[C].

71.11 km/hr

[D].

71 km/hr

Answer: Option C

Explanation:

Total time taken =		160	+	160	hrs.	=	9	hrs.
		64		80			2

Average speed =		320 x	2	km/hr	= 71.11 km/hr.
			9

Question:
A farmer travelled a distance of 61 km in 9 hours. He travelled partly on foot @ 4 km/hr and partly on bicycle @ 9 km/hr. The distance travelled on foot is:

[A].

14 km

[B].

15 km

[C].

16 km

[D].

17 km

Answer: Option C

Explanation:

Let the distance travelled on foot be x km.

Then, distance travelled on bicycle = (61 -x) km.

So,	x	+	(61 -x)	= 9
	4		9

9x + 4(61 -x) = 9 x 36

5x = 80

x = 16 km.

Question: An aeroplane covers a certain distance at a speed of 240 kmph in 5 hours. To cover the same distance in 1 hours, it must travel at a speed of:
[A].

300 kmph

[B].

360 kmph

[C].

600 kmph

[D].

720 kmph

Answer: Option D

Explanation:

Distance = (240 x 5) = 1200 km.

Speed = Distance/Time

Speed = 1200/(5/3) km/hr.     [We can write 1 hours as 5/3 hours]

Required speed =		1200 x	3	km/hr	= 720 km/hr.
			5

Question: The ratio between the speeds of two trains is 7 : 8. If the second train runs 400 km in 4 hours, then the speed of the first train is:
[A].

70 km/hr

[B].

75 km/hr

[C].

84 km/hr

[D].

87.5 km/hr

Answer: Option D

Explanation:

Let the speed of two trains be 7x and 8x km/hr.

Then, 8x =		400		= 100
		4

x =		100		= 12.5
		8

Speed of first train = (7 x 12.5) km/hr = 87.5 km/hr.