Aptitude

The calendar for the year 2007 will be the same for the year:

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Question:
The calendar for the year 2007 will be the same for the year:

[A].

2014

[B].

2016

[C].

2017

[D].

2018

Answer: Option D

Explanation:

Count the number of odd days from the year 2007 onwards to get the sum equal to 0 odd day.

Year : 2007 2008 2009 2010 2011 2012 2013 2014 2015 2016 2017
Odd day : 1 2 1 1 1 2 1 1 1 2 1

Sum = 14 odd days 0 odd days.

Calendar for the year 2018 will be the same as for the year 2007.

If 6th March, 2005 is Monday, what was the day of the week on 6th March, 2004?

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Question: If 6th March, 2005 is Monday, what was the day of the week on 6th March, 2004?
[A].

Sunday

[B].

Saturday

[C].

Tuesday

[D].

Wednesday

Answer: Option A

Explanation:

The year 2004 is a leap year. So, it has 2 odd days.

But, Feb 2004 not included because we are calculating from March 2004 to March 2005. So it has 1 odd day only.

The day on 6th March, 2005 will be 1 day beyond the day on 6th March, 2004.

Given that, 6th March, 2005 is Monday.

6th March, 2004 is Sunday (1 day before to 6th March, 2005).

On 8th Dec, 2007 Saturday falls. What day of the week was it on 8th Dec, 2006?

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Question:
On 8th Dec, 2007 Saturday falls. What day of the week was it on 8th Dec, 2006?

[A].

Sunday

[B].

Thursday

[C].

Tuesday

[D].

Friday

Answer: Option D

Explanation:

The year 2006 is an ordinary year. So, it has 1 odd day.

So, the day on 8th Dec, 2007 will be 1 day beyond the day on 8th Dec, 2006.

But, 8th Dec, 2007 is Saturday.

8th Dec, 2006 is Friday.

A man rows to a place 48 km distant and come back in 14 hours. He finds that he can row 4 km with the stream in the same time as 3 km against the stream. The rate of the stream is:

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Question:
A man rows to a place 48 km distant and come back in 14 hours. He finds that he can row 4 km with the stream in the same time as 3 km against the stream. The rate of the stream is:

[A].

1 km/hr

[B].

1.5 km/hr

[C].

2 km/hr

[D].

2.5 km/hr

Answer: Option A

Explanation:

Suppose he move 4 km downstream in x hours. Then,

Speed downstream = 4 km/hr.
x
Speed upstream = 3 km/hr.
x
48 + 48 = 14 or x = 1 .
(4/x) (3/x) 2

So, Speed downstream = 8 km/hr, Speed upstream = 6 km/hr.

Rate of the stream = 1 (8 – 6) km/hr = 1 km/hr.
2

A boat takes 90 minutes less to travel 36 miles downstream than to travel the same distance upstream. If the speed of the boat in still water is 10 mph, the speed of the stream is:

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Question: A boat takes 90 minutes less to travel 36 miles downstream than to travel the same distance upstream. If the speed of the boat in still water is 10 mph, the speed of the stream is:
[A].

2 mph

[B].

2.5 mph

[C].

3 mph

[D].

4 mph

Answer: Option A

Explanation:

Let the speed of the stream x mph. Then,

Speed downstream = (10 + x) mph,

Speed upstream = (10 – x) mph.

36 – 36 = 90
(10 – x) (10 + x) 60

72x x 60 = 90 (100 – x2)

x2 + 48x – 100 = 0

(x+ 50)(x – 2) = 0

x = 2 mph.

A motorboat, whose speed in 15 km/hr in still water goes 30 km downstream and comes back in a total of 4 hours 30 minutes. The speed of the stream (in km/hr) is:

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Question: A motorboat, whose speed in 15 km/hr in still water goes 30 km downstream and comes back in a total of 4 hours 30 minutes. The speed of the stream (in km/hr) is:
[A].

4

[B].

5

[C].

6

[D].

10

Answer: Option B

Explanation:

Let the speed of the stream be x km/hr. Then,

Speed downstream = (15 + x) km/hr,

Speed upstream = (15 – x) km/hr.

30 + 30 = 4 1
(15 + x) (15 – x) 2
900 = 9
225 – x2 2

9×2 = 225

x2 = 25

x = 5 km/hr.

Video Explanation: https://youtu.be/lMFnNB3YQOo

A boat covers a certain distance downstream in 1 hour, while it comes back in 1 hours. If the speed of the stream be 3 kmph, what is the speed of the boat in still water?

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Question:
A boat covers a certain distance downstream in 1 hour, while it comes back in 1 hours. If the speed of the stream be 3 kmph, what is the speed of the boat in still water?

[A].

12 kmph

[B].

13 kmph

[C].

14 kmph

[D].

15 kmph

Answer: Option D

Explanation:

Let the speed of the boat in still water be x kmph. Then,

Speed downstream = (x + 3) kmph,

Speed upstream = (x – 3) kmph.

(x + 3) x 1 = (x – 3) x 3
2

2x + 6 = 3x – 9

x = 15 kmph.

A man can row at 5 kmph in still water. If the velocity of current is 1 kmph and it takes him 1 hour to row to a place and come back, how far is the place?

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Question:
A man can row at 5 kmph in still water. If the velocity of current is 1 kmph and it takes him 1 hour to row to a place and come back, how far is the place?

[A].

2.4 km

[B].

2.5 km

[C].

3 km

[D].

3.6 km

Answer: Option A

Explanation:

Speed downstream = (5 + 1) kmph = 6 kmph.

Speed upstream = (5 – 1) kmph = 4 kmph.

Let the required distance be x km.

Then, x + x = 1
6 4

2x + 3x = 12

5x = 12

x = 2.4 km.