The rational number for recurring decimal 0.125125…. is:
[A].
| 63 |
| 487 |
[B].
| 119 |
| 993 |
[C].
| 125 |
| 999 |
[D].
Answer: Option C
Explanation:
| 0.125125… = 0.125 = | 125 |
| 999 |
| 63 |
| 487 |
[B].
| 119 |
| 993 |
[C].
| 125 |
| 999 |
[D].
Answer: Option C
Explanation:
| 0.125125… = 0.125 = | 125 |
| 999 |
| 1 |
| 5 |
[B].
| 2 |
| 9 |
[C].
| 23 |
| 99 |
[D].
| 23 |
| 100 |
Answer: Option C
Explanation:
| 0.232323… = 0.23 = | 23 |
| 99 |
[B].
[C].
[D].
Answer: Option B
Explanation:
Suppose commodity X will cost 40 paise more than Y after z years.
Then, (4.20 + 0.40z) – (6.30 + 0.15z) = 0.40
0.25z = 0.40 + 2.10
| z = | 2.50 | = | 250 | = 10. |
| 0.25 | 25 |
X will cost 40 paise more than Y 10 years after 2001 i.e., 2011.
[B].
[C].
[D].
Answer: Option C
Explanation:
| 4.036 | = | 403.6 | = 100.9 |
| 0.04 | 4 |
[B].
[C].
[D].
Answer: Option B
Explanation:
Sum of decimal places = 7.
Since the last digit to the extreme right will be zero (since 5 x 4 = 20), so there will be 6 significant digits to the right of the decimal point.
[B].
[C].
[D].
Answer: Option B
Explanation:
4 x 162 = 648. Sum of decimal places = 6.
So, 0.04 x 0.0162 = 0.000648 = 6.48 x 10-4
[B].
[C].
[D].
Answer: Option B
Explanation:
2 x 5 = 10.
Sum of decimal places = 4
0.002 x 0.5 = 0.001
[B].
[C].
[D].
Answer: Option C
Explanation:
3.14 x 106 = 3.14 x 1000000 = 3140000.
[B].
[C].
[D].
Answer: Option D
Explanation:
Let 3889 + 12.952 – x = 3854.002.
Then x = (3889 + 12.952) – 3854.002
= 3901.952 – 3854.002
= 47.95.
[B].
[C].
[D].
Answer: Option C
Explanation:
617.00
6.017
0.617
+ 6.0017
——–
629.6357
———