Aptitude

Question:
In a division sum, the divisor is 10 times the quotient and 5 times the remainder. If the remainder is 46, what is the dividend ?

[A].

4236

[B].

4306

[C].

4336

[D].

5336

Answer: Option D

Explanation:

Divisor = (5 x 46) = 230

10 x Quotient = 230     =	230	= 23
	10

Dividend = (Divisor x Quotient) + Remainder

    = (230 x 23) + 46

    = 5290 + 46

    = 5336.

Question: What is the unit digit in {(6374)1793 x (625)317 x (341491)}?
[A].

0 

[B].

2

[C].

3

[D].

5

Answer: Option A

Explanation:

Unit digit in (6374)1793 = Unit digit in (4)1793

    = Unit digit in [(42)896 x 4]

    = Unit digit in (6 x 4) = 4

Unit digit in (625)317 = Unit digit in (5)317 = 5

Unit digit in (341)491 = Unit digit in (1)491 = 1

Required digit = Unit digit in (4 x 5 x 1) = 0.

Question:
The smallest 6 digit number exactly divisible by 111 is:

[A].

111111

[B].

110011

[C].

100011

[D].

110101

Answer: Option C

Explanation:

The smallest 6-digit number 100000.

111) 100000 (900
999
—–
100
—

Required number = 100000 + (111 – 100)
= 100011.

Question:
The smallest 5 digit number exactly divisible by 41 is:

[A].

1004

[B].

10004

[C].

10045

[D].

10025

Answer: Option B

Explanation:

The smallest 5-digit number = 10000.

41) 10000 (243
82
—
180
164
—-
160
123
—
37
—

Required number = 10000 + (41 – 37)
= 10004.

Question: What least number must be added to 1056, so that the sum is completely divisible by 23 ?
[A].

2

[B].

3

[C].

18

[D].

21

Answer: Option A

Explanation:

23) 1056 (45
92
—
136
115
—
21
—

Required number = (23 – 21)
= 2.

Question:
What least number must be subtracted from 13601, so that the remainder is divisible by 87 ?

[A].

23

[B].

31

[C].

29

[D].

37

Answer: Option C

Explanation:

87) 13601 (156
87
—-
490
435
—-
551
522
—
29
—

Therefore, the required number = 29.

Question:
The largest 5 digit number exactly divisible by 91 is:

[A].

99921

[B].

99918

[C].

99981

[D].

99971

Answer: Option B

Explanation:

Largest 5-digit number = 99999

91) 99999 (1098
91
—
899
819
—-
809
728
—
81
—

Required number = (99999 – 81)
= 99918.

Question: The largest 4 digit number exactly divisible by 88 is:
[A].

9944

[B].

9768

[C].

9988

[D].

8888

Answer: Option A

Explanation:

Largest 4-digit number = 9999

88) 9999 (113
88
—-
119
88
—-
319
264
—
55
—

Required number = (9999 – 55)
= 9944.

Question: Which natural number is nearest to 8485, which is completely divisible by 75 ?
[A].

8475

[B].

8500

[C].

8550

[D].

8525

Answer: Option A

Explanation:

On dividing, we get

75) 8485 (113
75
—
98
75
—-
235
225
—
10
—

Required number = (8485 – 10) // Because 10

Question: Which natural number is nearest to 9217, which is completely divisible by 88 ?
[A].

9152

[B].

9240

[C].

9064

[D].

9184

Answer: Option B

Explanation:

On dividing we get,

88) 9217 (104
88
—-
417
352
—-
65
—-

Therefore, Required number = 9217 + (88 – 65) // Because (88 – 65)