[A].
[B].
[C].
[D].
Answer: Option D
Explanation:
| (A + B)’s 20 day’s work = | 1 | x 20 | = | 2 | . | ||
| 30 | 3 |
| Remaining work = | 1 – | 2 | = | 1 | . | ||
| 3 | 3 |
| Now, | 1 | work is done by A in 20 days. |
| 3 |
Therefore, the whole work will be done by A in (20 x 3) = 60 days.
[B].
[C].
[D].
Answer: Option D
Explanation:
| (A + B)’s 20 day’s work = | 1 | x 20 | = | 2 | . | ||
| 30 | 3 |
| Remaining work = | 1 – | 2 | = | 1 | . | ||
| 3 | 3 |
| Now, | 1 | work is done by A in 20 days. |
| 3 |
Therefore, the whole work will be done by A in (20 x 3) = 60 days.
[B].
[C].
[D].
Answer: Option A
Explanation:
| 2(A + B + C)’s 1 day’s work = | 1 | + | 1 | + | 1 | = | 15 | = | 1 | . | ||
| 30 | 24 | 20 | 120 | 8 |
| Therefore, (A + B + C)’s 1 day’s work = | 1 | = | 1 | . |
| 2 x 8 | 16 |
| Work done by A, B, C in 10 days = | 10 | = | 5 | . |
| 16 | 8 |
| Remaining work = | 1 – | 5 | = | 3 | . | ||
| 8 | 8 |
| A’s 1 day’s work = | 1 | – | 1 | = | 1 | . | ||
| 16 | 24 | 48 |
| Now, | 1 | work is done by A in 1 day. |
| 48 |
| So, | 3 | work will be done by A in | 48 x | 3 | = 18 days. | ||
| 8 | 8 |
[B].
[C].
[D].
Answer: Option D
Explanation:
| (P + Q + R)’s 1 hour’s work = | 1 | + | 1 | + | 1 | = | 37 | . | ||
| 8 | 10 | 12 | 120 |
| Work done by P, Q and R in 2 hours = | 37 | x 2 | = | 37 | . | ||
| 120 | 60 |
| Remaining work = | 1 – | 37 | = | 23 | . | ||
| 60 | 60 |
| (Q + R)’s 1 hour’s work = | 1 | + | 1 | = | 11 | . | ||
| 10 | 12 | 60 |
| Now, | 11 | work is done by Q and R in 1 hour. |
| 60 |
| So, | 23 | work will be done by Q and R in | 60 | x | 23 | = | 23 | hours 2 hours. | ||
| 60 | 11 | 60 | 11 |
So, the work will be finished approximately 2 hours after 11 A.M., i.e., around 1 P.M.
[B].
[C].
[D].
Answer: Option C
Explanation:
| (A + B)’s 1 day’s work = | 1 | + | 1 | = | 1 | . | ||
| 15 | 10 | 6 |
| Work done by A and B in 2 days = | 1 | x 2 | = | 1 | . | ||
| 6 | 3 |
| Remaining work = | 1 – | 1 | = | 2 | . | ||
| 3 | 3 |
| Now, | 1 | work is done by A in 1 day. |
| 15 |
| 2 | work will be done by a in | 15 x | 2 | = 10 days. | |||
| 3 | 3 |
Hence, the total time taken = (10 + 2) = 12 days.
[B].
| 5 | 1 |
| 2 |
[C].
[D].
Answer: Option C
Explanation:
| B’s 10 day’s work = | 1 | x 10 | = | 2 | . | ||
| 15 | 3 |
| Remaining work = | 1 – | 2 | = | 1 | . | ||
| 3 | 3 |
| Now, | 1 | work is done by A in 1 day. |
| 18 |
| 1 | work is done by A in | 18 x | 1 | = 6 days. | |||
| 3 | 3 |
| 1 |
| 4 |
[B].
| 1 |
| 10 |
[C].
| 7 |
| 15 |
[D].
| 8 |
| 15 |
Answer: Option D
Explanation:
| A’s 1 day’s work = | 1 | ; |
| 15 |
| B’s 1 day’s work = | 1 | ; |
| 20 |
| (A + B)’s 1 day’s work = | 1 | + | 1 | = | 7 | . | ||
| 15 | 20 | 60 |
| (A + B)’s 4 day’s work = | 7 | x 4 | = | 7 | . | ||
| 60 | 15 |
| Therefore, Remaining work = | 1 – | 7 | = | 8 | . | ||
| 15 | 15 |
[B].
[C].
| 20 | 3 | days |
| 17 |
[D].
Answer: Option B
Explanation:
Ratio of times taken by A and B = 100 : 130 = 10 : 13.
Suppose B takes x days to do the work.
| Then, 10 : 13 :: 23 : x x = | 23 x 13 | x = | 299 | . | ||
| 10 | 10 |
| A’s 1 day’s work = | 1 | ; |
| 23 |
| B’s 1 day’s work = | 10 | . |
| 299 |
| (A + B)’s 1 day’s work = | 1 | + | 10 | = | 23 | = | 1 | . | ||
| 23 | 299 | 299 | 13 |
Therefore, A and B together can complete the work in 13 days.
| 9 | 1 | days |
| 3 |
[B].
[C].
| 12 | 1 | days |
| 4 |
[D].
| 16 | 1 | days |
| 3 |
Answer: Option B
Explanation:
| (A’s 1 day’s work) : (B’s 1 day’s work) = | 7 | : 1 = 7 : 4. |
| 4 |
Let A’s and B’s 1 day’s work be 7x and 4x respectively.
| Then, 7x + 4x = | 1 | 11x = | 1 | x = | 1 | . |
| 7 | 7 | 77 |
| A’s 1 day’s work = | 1 | x 7 | = | 1 | . | ||
| 77 | 11 |
[B].
[C].
[D].
Answer: Option A
Explanation:
Ratio of rates of working of A and B = 2 : 1.
So, ratio of times taken = 1 : 2.
| B’s 1 day’s work = | 1 | . |
| 12 |
| A’s 1 day’s work = | 1 | ; (2 times of B’s work) |
| 6 |
| (A + B)’s 1 day’s work = | 1 | + | 1 | = | 3 | = | 1 | . | ||
| 6 | 12 | 12 | 4 |
So, A and B together can finish the work in 4 days.
[B].
[C].
[D].
Answer: Option C
Explanation:
| A’s 1 hour’s work = | 1 | ; |
| 4 |
| (B + C)’s 1 hour’s work = | 1 | ; |
| 3 |
| (A + C)’s 1 hour’s work = | 1 | . |
| 2 |
| (A + B + C)’s 1 hour’s work = | 1 | + | 1 | = | 7 | . | ||
| 4 | 3 | 12 |
| B’s 1 hour’s work = | 7 | – | 1 | = | 1 | . | ||
| 12 | 2 | 12 |
B alone will take 12 hours to do the work.