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Aptitude

The product of two numbers is 2028 and their H.C.F. is 13. The number of such pairs is:

Aptitude, Problems on H.C.F and L.C.M /
Question: The product of two numbers is 2028 and their H.C.F. is 13. The number of such pairs is:

[A].

1

[B].

2

[C].

3

[D].

4

Answer: Option B

Explanation:

Let the numbers 13a and 13b.

Then, 13a x 13b = 2028

ab = 12.

Now, the co-primes with product 12 are (1, 12) and (3, 4).

[Note: Two integers a and b are said to be coprime or relatively prime if they have no common positive factor other than 1 or, equivalently, if their greatest common divisor is 1 ]

So, the required numbers are (13 x 1, 13 x 12) and (13 x 3, 13 x 4).

Clearly, there are 2 such pairs.

The product of two numbers is 2028 and their H.C.F. is 13. The number of such pairs is: Read More »

Aptitude, Problems on H.C.F and L.C.M

The product of two numbers is 4107. If the H.C.F. of these numbers is 37, then the greater number is:

Aptitude, Problems on H.C.F and L.C.M /
Question: The product of two numbers is 4107. If the H.C.F. of these numbers is 37, then the greater number is:

[A].

101

[B].

107

[C].

111

[D].

185

Answer: Option C

Explanation:

Let the numbers be 37a and 37b.

Then, 37a x 37b = 4107

ab = 3.

Now, co-primes with product 3 are (1, 3).

So, the required numbers are (37 x 1, 37 x 3) i.e., (37, 111).

Greater number = 111.

The product of two numbers is 4107. If the H.C.F. of these numbers is 37, then the greater number is: Read More »

Aptitude, Problems on H.C.F and L.C.M

The ratio of two numbers is 3 : 4 and their H.C.F. is 4. Their L.C.M. is:

Aptitude, Problems on H.C.F and L.C.M /
Question:
The ratio of two numbers is 3 : 4 and their H.C.F. is 4. Their L.C.M. is:

[A].

12

[B].

16

[C].

24

[D].

48

Answer: Option D

Explanation:

Let the numbers be 3x and 4x. Then, their H.C.F. = x. So, x = 4.

So, the numbers 12 and 16.

L.C.M. of 12 and 16 = 48.

The ratio of two numbers is 3 : 4 and their H.C.F. is 4. Their L.C.M. is: Read More »

Aptitude, Problems on H.C.F and L.C.M

Ayesha’s father was 38 years of age when she was born while her mother was 36 years old when her brother four years younger to her was born. What is the difference between the ages of her parents?

Aptitude, Problems On Ages /
Question:
Ayesha’s father was 38 years of age when she was born while her mother was 36 years old when her brother four years younger to her was born. What is the difference between the ages of her parents?

[A].

2 years

[B].

4 years

[C].

6 years

[D].

8 years

Answer: Option C

Explanation:

Mother’s age when Ayesha’s brother was born = 36 years.

Father’s age when Ayesha’s brother was born = (38 + 4) years = 42 years.

Required difference = (42 – 36) years = 6 years.

Ayesha’s father was 38 years of age when she was born while her mother was 36 years old when her brother four years younger to her was born. What is the difference between the ages of her parents? Read More »

Aptitude, Problems On Ages

A father said to his son, “I was as old as you are at the present at the time of your birth”. If the father’s age is 38 years now, the son’s age five years back was:

Aptitude, Problems On Ages /
Question:
A father said to his son, “I was as old as you are at the present at the time of your birth”. If the father’s age is 38 years now, the son’s age five years back was:

[A].

14 years

[B].

19 years

[C].

33 years

[D].

38 years

Answer: Option A

Explanation:

Let the son’s present age be x years. Then, (38 – x) = x

2x = 38.

x = 19.

Son’s age 5 years back (19 – 5) = 14 years.

A father said to his son, “I was as old as you are at the present at the time of your birth”. If the father’s age is 38 years now, the son’s age five years back was: Read More »

Aptitude, Problems On Ages

Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit’s age. After further 8 years, how many times would he be of Ronit’s age?

Aptitude, Problems On Ages /
Question:
Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit’s age. After further 8 years, how many times would he be of Ronit’s age?

[A].

2 times

[B].

2  1 times
2

[C].

2  3 times
4

[D].

3 times

Answer: Option A

Explanation:

Let Ronit’s present age be x years. Then, father’s present age =(x + 3x) years = 4x years.

(4x + 8) = 5 (x + 8)
2

8x + 16 = 5x + 40

3x = 24

x = 8.

Hence, required ratio = (4x + 16) = 48 = 2.
(x + 16) 24

Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit’s age. After further 8 years, how many times would he be of Ronit’s age? Read More »

Aptitude, Problems On Ages

The sum of ages of 5 children born at the intervals of 3 years each is 50 years. What is the age of the youngest child?

Aptitude, Problems On Ages /
Question:
The sum of ages of 5 children born at the intervals of 3 years each is 50 years. What is the age of the youngest child?

[A].

4 years

[B].

8 years

[C].

10 years

[D].

None of these

Answer: Option A

Explanation:

Let the ages of children be x, (x + 3), (x + 6), (x + 9) and (x + 12) years.

Then, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50

5x = 20

x = 4.

Age of the youngest child = x = 4 years.

The sum of ages of 5 children born at the intervals of 3 years each is 50 years. What is the age of the youngest child? Read More »

Aptitude, Problems On Ages

Q is as much younger than R as he is older than T. If the sum of the ages of R and T is 50 years, what is definitely the difference between R and Q’s age?

Aptitude, Problems On Ages /
Question: Q is as much younger than R as he is older than T. If the sum of the ages of R and T is 50 years, what is definitely the difference between R and Q’s age?
[A].

1 year

[B].

2 years

[C].

25 years

[D].

Data inadequate

Answer: Option D

Explanation:

Given that:

1. The difference of age b/w R and Q = The difference of age b/w Q and T.

2. Sum of age of R and T is 50 i.e. (R + T) = 50.

Question: R – Q = ?.

Explanation:

R – Q = Q – T

(R + T) = 2Q

Now given that, (R + T) = 50

So, 50 = 2Q and therefore Q = 25.

Question is (R – Q) = ?

Here we know the value(age) of Q (25), but we don’t know the age of R.

Therefore, (R-Q) cannot be determined.

Q is as much younger than R as he is older than T. If the sum of the ages of R and T is 50 years, what is definitely the difference between R and Q’s age? Read More »

Aptitude, Problems On Ages