If Rs. 782 be divided into three parts, proportional to : : , then the first part is:
[A].
[B].
[C].
[D].
Answer: Option D
Explanation:
Given ratio = : : = 6 : 8 : 9.
| 1st part = Rs. | 782 x | 6 | = Rs. 204 | ||
| 23 |
[B].
[C].
[D].
Answer: Option D
Explanation:
Given ratio = : : = 6 : 8 : 9.
| 1st part = Rs. | 782 x | 6 | = Rs. 204 | ||
| 23 |
[B].
[C].
[D].
Answer: Option C
Explanation:
Let A = 2k, B = 3k and C = 5k.
| A’s new salary = | 115 | of 2k = | 115 | x 2k | = | 23k | ||
| 100 | 100 | 10 |
| B’s new salary = | 110 | of 3k = | 110 | x 3k | = | 33k | ||
| 100 | 100 | 10 |
| C’s new salary = | 120 | of 5k = | 120 | x 5k | = 6k | ||
| 100 | 100 |
| New ratio | 23k | : | 33k | : 6k | = 23 : 33 : 60 | ||
| 10 | 10 |
[B].
[C].
[D].
Answer: Option B
Explanation:
| (x x 5) = (0.75 x 8) x = | 6 | = 1.20 | ||
| 5 |
[B].
[C].
[D].
Answer: Option C
Explanation:
A : B = 60 : 45.
A : C = 60 : 40.
| B | = | B | x | A | = | 45 | x | 60 | = | 45 | = | 90 | = 90 : 80. | |||||
| C | A | C | 60 | 40 | 40 | 80 |
B can give C 10 points in a game of 90.
[B].
[C].
[D].
Answer: Option B
Explanation:
A : B = 100 : 80.
A : C = 100 : 72.
| B | = | B | x | A | = | 80 | x | 100 | = | 10 | = | 100 | = 100 : 90. | |||||
| C | A | C | 100 | 72 | 9 | 90 |
B can give C 10 points.
[B].
[C].
[D].
Answer: Option B
Explanation:
| A’s speed = | 5 x | 5 | m/sec | = | 25 | m/sec. | |
| 18 | 18 |
| Time taken by A to cover 100 m = | 100 x | 18 | sec | = 72 sec. | |
| 25 |
Time taken by B to cover 92 m = (72 + 8) = 80 sec.
| B’s speed = | 92 | x | 18 | kmph | = 4.14 kmph. | |
| 80 | 5 |
[B].
[C].
[D].
| 7 | 4 | m |
| 7 |
Answer: Option B
Explanation:
A : B = 200 : 169.
A : C = 200 : 182.
| C | = | C | x | A | = | 182 | x | 200 | = 182 : 169. | ||||
| B | A | B | 200 | 169 |
When C covers 182 m, B covers 169 m.
| When C covers 350 m, B covers | 169 | x 350 | m | = 325 m. | |
| 182 |
Therefore, C beats B by (350 – 325) m = 25 m.
[B].
[C].
[D].
Answer: Option D
Explanation:
A : B = 100 : 90.
A : C = 100 : 87.
| B | = | B | x | A | = | 90 | x | 100 | = | 30 | . |
| C | A | C | 100 | 87 | 29 |
When B runs 30 m, C runs 29 m.
| When B runs 180 m, C runs | 29 | x 180 | m | = 174 m. | |
| 30 |
B beats C by (180 – 174) m = 6 m.
[B].
[C].
[D].
Answer: Option B
Explanation:
A : B = 100 : 90.
A : C = 100 : 72.
| B : C = | B | x | A | = | 90 | x | 100 | = | 90 | . |
| A | C | 100 | 72 | 72 |
When B runs 90 m, C runs 72 m.
| When B runs 100 m, C runs | 72 | x 100 | m | = 80 m. | |
| 90 |
B can give C 20 m.
[B].
[C].
[D].
Answer: Option C
Explanation:
A : B = 100 : 75
B : C = 100 : 96.
| A : C = | A | x | B | = | 100 | x | 100 | = | 100 | = 100 : 72. | ||||
| B | C | 75 | 96 | 72 |
A beats C by (100 – 72) m = 28 m.