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Aptitude

Free notebooks were distributed equally among children of a class. The number of notebooks each child got was one-eighth of the number of children. Had the number of children been half, each child would have got 16 notebooks. Total how many notebooks were distributed ?

Question:
Free notebooks were distributed equally among children of a class. The number of notebooks each child got was one-eighth of the number of children. Had the number of children been half, each child would have got 16 notebooks. Total how many notebooks were distributed ?

[A].

256

[B].

432

[C].

512

[D].

640

Answer: Option C

Explanation:

Let total number of children be x.

Then, x x 1 x = x x 16     x = 64.
8 2
Number of notebooks = 1 x2 = 1 x 64 x 64 = 512.
8 8

Free notebooks were distributed equally among children of a class. The number of notebooks each child got was one-eighth of the number of children. Had the number of children been half, each child would have got 16 notebooks. Total how many notebooks were distributed ? Read More »

Aptitude, Simplification

David gets on the elevator at the 11th floor of a building and rides up at the rate of 57 floors per minute. At the same time, Albert gets on an elevator at the 51st floor of the same building and rides down at the rate of 63 floors per minute. If they continue travelling at these rates, then at which floor will their paths cross ?

Question:
David gets on the elevator at the 11th floor of a building and rides up at the rate of 57 floors per minute. At the same time, Albert gets on an elevator at the 51st floor of the same building and rides down at the rate of 63 floors per minute. If they continue travelling at these rates, then at which floor will their paths cross ?

[A].

19

[B].

28

[C].

30

[D].

37

Answer: Option C

Explanation:

Suppose their paths cross after x minutes.

Then, 11 + 57x = 51 – 63x       120x = 40

x = 1
3
Number of floors covered by David in (1/3) min. = 1 x 57 = 19.
3

So, their paths cross at (11 +19) i.e., 30th floor.

David gets on the elevator at the 11th floor of a building and rides up at the rate of 57 floors per minute. At the same time, Albert gets on an elevator at the 51st floor of the same building and rides down at the rate of 63 floors per minute. If they continue travelling at these rates, then at which floor will their paths cross ? Read More »

Aptitude, Simplification

A fires 5 shots to B’s 3 but A kills only once in 3 shots while B kills once in 2 shots. When B has missed 27 times, A has killed:

Question:
A fires 5 shots to B’s 3 but A kills only once in 3 shots while B kills once in 2 shots. When B has missed 27 times, A has killed:

[A].

30 birds

[B].

60 birds

[C].

72 birds

[D].

90 birds

Answer: Option A

Explanation:

Let the total number of shots be x. Then,

Shots fired by A = 5 x
8
Shots fired by B = 3 x
8
Killing shots by A = 1 of 5 x = 5 x
3 8 24
Shots missed by B = 1 of 3 x = 3 x
2 8 16
3x = 27 or x = 27 x 16 = 144.
16 3
Birds killed by A = 5x = 5 x 144 = 30.
24 24

A fires 5 shots to B’s 3 but A kills only once in 3 shots while B kills once in 2 shots. When B has missed 27 times, A has killed: Read More »

Aptitude, Simplification

To fill a tank, 25 buckets of water is required. How many buckets of water will be required to fill the same tank if the capacity of the bucket is reduced to two-fifth of its present ?

Question:
To fill a tank, 25 buckets of water is required. How many buckets of water will be required to fill the same tank if the capacity of the bucket is reduced to two-fifth of its present ?

[A].

10

[B].

35

[C].

62.5

[D].

Cannot be determined

Answer: Option C

Explanation:

Let the capacity of 1 bucket = x.

Then, the capacity of tank = 25x.

New capacity of bucket = 2 x
5
Required number of buckets = 25x
(2x/5)
= 25x x 5
2x
= 125
2

= 62.5

To fill a tank, 25 buckets of water is required. How many buckets of water will be required to fill the same tank if the capacity of the bucket is reduced to two-fifth of its present ? Read More »

Aptitude, Simplification

A sum of Rs. 1360 has been divided among A, B and C such that A gets of what B gets and B gets of what C gets. B’s share is:

Question:
A sum of Rs. 1360 has been divided among A, B and C such that A gets of what B gets and B gets of what C gets. B’s share is:

[A].

Rs. 120

[B].

Rs. 160

[C].

Rs. 240

[D].

Rs. 300

Answer: Option C

Explanation:

Let C’s share = Rs. x

Then, B’s share = Rs. x ,   A’s share = Rs. 2 x x = Rs. x
4 3 4 6
x + x + x = 1360
6 4
17x = 1360
12
x = 1360 x 12 = Rs. 960
17
Hence, B’s share = Rs. 960 = Rs. 240.
4

A sum of Rs. 1360 has been divided among A, B and C such that A gets of what B gets and B gets of what C gets. B’s share is: Read More »

Aptitude, Simplification

One-third of Rahul’s savings in National Savings Certificate is equal to one-half of his savings in Public Provident Fund. If he has Rs. 1,50,000 as total savings, how much has he saved in Public Provident Fund ?

Question:
One-third of Rahul’s savings in National Savings Certificate is equal to one-half of his savings in Public Provident Fund. If he has Rs. 1,50,000 as total savings, how much has he saved in Public Provident Fund ?

[A].

Rs. 30,000

[B].

Rs. 50,000

[C].

Rs. 60,000

[D].

Rs. 90,000

Answer: Option C

Explanation:

Let savings in N.S.C and P.P.F. be Rs. x and Rs. (150000 – x) respectively. Then,

1 x = 1 (150000 – x)
3 2
x + x = 75000
3 2
5x = 75000
6
x = 75000 x 6 = 90000
5

Savings in Public Provident Fund = Rs. (150000 – 90000) = Rs. 60000

One-third of Rahul’s savings in National Savings Certificate is equal to one-half of his savings in Public Provident Fund. If he has Rs. 1,50,000 as total savings, how much has he saved in Public Provident Fund ? Read More »

Aptitude, Simplification

Mr. Thomas invested an amount of Rs. 13,900 divided in two different schemes A and B at the simple interest rate of 14% p.a. and 11% p.a. respectively. If the total amount of simple interest earned in 2 years be Rs. 3508, what was the amount invested in Scheme B?

Question: Mr. Thomas invested an amount of Rs. 13,900 divided in two different schemes A and B at the simple interest rate of 14% p.a. and 11% p.a. respectively. If the total amount of simple interest earned in 2 years be Rs. 3508, what was the amount invested in Scheme B?
[A].

Rs. 6400

[B].

Rs. 6500

[C].

Rs. 7200

[D].

Rs. 7500

Answer: Option A

Explanation:

Let the sum invested in Scheme A be Rs. x and that in Scheme B be Rs. (13900 – x).

Then, x x 14 x 2 + (13900 – x) x 11 x 2 = 3508
100 100

28x – 22x = 350800 – (13900 x 22)

6x = 45000

x = 7500.

So, sum invested in Scheme B = Rs. (13900 – 7500) = Rs. 6400.

Video Explanation: https://youtu.be/Xi4kU9y6ppk

Mr. Thomas invested an amount of Rs. 13,900 divided in two different schemes A and B at the simple interest rate of 14% p.a. and 11% p.a. respectively. If the total amount of simple interest earned in 2 years be Rs. 3508, what was the amount invested in Scheme B? Read More »

Aptitude, Simple Interest

A lent Rs. 5000 to B for 2 years and Rs. 3000 to C for 4 years on simple interest at the same rate of interest and received Rs. 2200 in all from both of them as interest. The rate of interest per annum is:

Question:
A lent Rs. 5000 to B for 2 years and Rs. 3000 to C for 4 years on simple interest at the same rate of interest and received Rs. 2200 in all from both of them as interest. The rate of interest per annum is:

[A].

5%

[B].

7%

[C].

7 1 %
8

[D].

10%

Answer: Option D

Explanation:

Let the rate be R% p.a.

Then, 5000 x R x 2 + 3000 x R x 4 = 2200.
100 100

100R + 120R = 2200

R = 2200 = 10.
220

Rate = 10%.

A lent Rs. 5000 to B for 2 years and Rs. 3000 to C for 4 years on simple interest at the same rate of interest and received Rs. 2200 in all from both of them as interest. The rate of interest per annum is: Read More »

Aptitude, Simple Interest

A sum of money at simple interest amounts to Rs. 815 in 3 years and to Rs. 854 in 4 years. The sum is:

Question: A sum of money at simple interest amounts to Rs. 815 in 3 years and to Rs. 854 in 4 years. The sum is:
[A].

Rs. 650

[B].

Rs. 690

[C].

Rs. 698

[D].

Rs. 700

Answer: Option C

Explanation:

S.I. for 1 year = Rs. (854 – 815) = Rs. 39.

S.I. for 3 years = Rs.(39 x 3) = Rs. 117.

Principal = Rs. (815 – 117) = Rs. 698.

A sum of money at simple interest amounts to Rs. 815 in 3 years and to Rs. 854 in 4 years. The sum is: Read More »

Aptitude, Simple Interest