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Area

A tank is 25 m long, 12 m wide and 6 m deep. The cost of plastering its walls and bottom at 75 paise per sq. m, is:

Question:
A tank is 25 m long, 12 m wide and 6 m deep. The cost of plastering its walls and bottom at 75 paise per sq. m, is:

[A].

Rs. 456

[B].

Rs. 458

[C].

Rs. 558

[D].

Rs. 568

Answer: Option C

Explanation:

Area to be plastered = [2(l + b) x h] + (l x b)
= {[2(25 + 12) x 6] + (25 x 12)} m2
= (444 + 300) m2
= 744 m2.
Cost of plastering = Rs. 744 x 75 = Rs. 558.
100

A tank is 25 m long, 12 m wide and 6 m deep. The cost of plastering its walls and bottom at 75 paise per sq. m, is: Read More »

Aptitude, Area

An error 2% in excess is made while measuring the side of a square. The percentage of error in the calculated area of the square is:

Question:
An error 2% in excess is made while measuring the side of a square. The percentage of error in the calculated area of the square is:

[A].

2%

[B].

2.02%

[C].

4%

[D].

4.04%

Answer: Option D

Explanation:

100 cm is read as 102 cm.

A1 = (100 x 100) cm2 and A2 (102 x 102) cm2.

(A2 – A1) = [(102)2 – (100)2]

= (102 + 100) x (102 – 100)

= 404 cm2.

Percentage error = 404 x 100 % = 4.04%
100 x 100

An error 2% in excess is made while measuring the side of a square. The percentage of error in the calculated area of the square is: Read More »

Aptitude, Area

A man walked diagonally across a square lot. Approximately, what was the percent saved by not walking along the edges?

Question:
A man walked diagonally across a square lot. Approximately, what was the percent saved by not walking along the edges?

[A].

20

[B].

24

[C].

30

[D].

33

Answer: Option C

Explanation:

Let the side of the square(ABCD) be x metres.

Then, AB + BC = 2x metres.

AC = 2x = (1.41x) m.

Saving on 2x metres = (0.59x) m.

Saving % = 0.59x x 100 % = 30% (approx.)
2x

A man walked diagonally across a square lot. Approximately, what was the percent saved by not walking along the edges? Read More »

Aptitude, Area

What is the least number of squares tiles required to pave the floor of a room 15 m 17 cm long and 9 m 2 cm broad?

Question:
What is the least number of squares tiles required to pave the floor of a room 15 m 17 cm long and 9 m 2 cm broad?

[A].

814

[B].

820

[C].

840

[D].

844

Answer: Option A

Explanation:

Length of largest tile = H.C.F. of 1517 cm and 902 cm = 41 cm.

Area of each tile = (41 x 41) cm2.

Required number of tiles = 1517 x 902 = 814.
41 x 41

What is the least number of squares tiles required to pave the floor of a room 15 m 17 cm long and 9 m 2 cm broad? Read More »

Aptitude, Area

A rectangular park 60 m long and 40 m wide has two concrete crossroads running in the middle of the park and rest of the park has been used as a lawn. If the area of the lawn is 2109 sq. m, then what is the width of the road?

Question: A rectangular park 60 m long and 40 m wide has two concrete crossroads running in the middle of the park and rest of the park has been used as a lawn. If the area of the lawn is 2109 sq. m, then what is the width of the road?
[A].

2.91 m

[B].

3 m

[C].

5.82 m

[D].

None of these

Answer: Option B

Explanation:

Area of the park = (60 x 40) m2 = 2400 m2.

Area of the lawn = 2109 m2.

Area of the crossroads = (2400 – 2109) m2 = 291 m2.

Let the width of the road be x metres. Then,

60x + 40x – x2 = 291

x2 – 100x + 291 = 0

(x – 97)(x – 3) = 0

x = 3.

Video Explanation: https://youtu.be/R3CtrAKGxkc

A rectangular park 60 m long and 40 m wide has two concrete crossroads running in the middle of the park and rest of the park has been used as a lawn. If the area of the lawn is 2109 sq. m, then what is the width of the road? Read More »

Aptitude, Area

The length of a rectangle is halved, while its breadth is tripled. What is the percentage change in area?

Question:
The length of a rectangle is halved, while its breadth is tripled. What is the percentage change in area?

[A].

25% increase

[B].

50% increase

[C].

50% decrease

[D].

75% decrease

Answer: Option B

Explanation:

Let original length = x and original breadth = y.

Original area = xy.

New length = x .
2

New breadth = 3y.

New area = x x 3y = 3 xy.
2 2
Increase % = 1 xy x 1 x 100 % = 50%.
2 xy

The length of a rectangle is halved, while its breadth is tripled. What is the percentage change in area? Read More »

Aptitude, Area

A towel, when bleached, was found to have lost 20% of its length and 10% of its breadth. The percentage of decrease in area is:

Question:
A towel, when bleached, was found to have lost 20% of its length and 10% of its breadth. The percentage of decrease in area is:

[A].

10%

[B].

10.08%

[C].

20%

[D].

28%

Answer: Option D

Explanation:

Let original length = x and original breadth = y.

Decrease in area
= xy – 80 x x 90 y
100 100
= xy – 18 xy
25
= 7 xy.
25
Decrease % = 7 xy x 1 x 100 % = 28%.
25 xy

A towel, when bleached, was found to have lost 20% of its length and 10% of its breadth. The percentage of decrease in area is: Read More »

Aptitude, Area

The percentage increase in the area of a rectangle, if each of its sides is increased by 20% is:

Question: The percentage increase in the area of a rectangle, if each of its sides is increased by 20% is:
[A].

40%

[B].

42%

[C].

44%

[D].

46%

Answer: Option C

Explanation:

Let original length = x metres and original breadth = y metres.

Original area = (xy) m2.

New length = 120 x m = 6 x m.
100 5
New breadth = 120 y m = 6 y m.
100 5
New Area = 6 x x 6 y m2 = 36 xy m2.
5 5 25

The difference between the original area = xy and new-area 36/25 xy is

= (36/25)xy – xy

= xy(36/25 – 1)

= xy(11/25) or (11/25)xy

Increase % = 11 xy x 1 x 100 % = 44%.
25 xy

Video Explanation: https://youtu.be/I3jLjLPn1W4

The percentage increase in the area of a rectangle, if each of its sides is increased by 20% is: Read More »

Aptitude, Area

The diagonal of a rectangle is 41 cm and its area is 20 sq. cm. The perimeter of the rectangle must be:

Question:
The diagonal of a rectangle is 41 cm and its area is 20 sq. cm. The perimeter of the rectangle must be:

[A].

9 cm

[B].

18 cm

[C].

20 cm

[D].

41 cm

Answer: Option B

Explanation:

l2 + b2 = 41.

Also, lb = 20.

(l + b)2 = (l2 + b2) + 2lb = 41 + 40 = 81

(l + b) = 9.

Perimeter = 2(l + b) = 18 cm.

The diagonal of a rectangle is 41 cm and its area is 20 sq. cm. The perimeter of the rectangle must be: Read More »

Aptitude, Area

The diagonal of the floor of a rectangular closet is 7 feet. The shorter side of the closet is 4 feet. What is the area of the closet in square feet?

Question:
The diagonal of the floor of a rectangular closet is 7 feet. The shorter side of the closet is 4 feet. What is the area of the closet in square feet?

[A].

5 1
4

[B].

13 1
2

[C].

27

[D].

37

Answer: Option C

Explanation:

Other side =
15 2 9 2
2 2
ft
=
225 81
4 4
ft
=
144
4
ft
= 6 ft.

Area of closet = (6 x 4.5) sq. ft = 27 sq. ft.

The diagonal of the floor of a rectangular closet is 7 feet. The shorter side of the closet is 4 feet. What is the area of the closet in square feet? Read More »

Aptitude, Area