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bca _ b _ aabc __ a __ caa

Question: bca _ b _ aabc __ a __ caa
[A].

acab

[B].

bcbb

[C].

cbab

[D].

ccab

Answer: Option A

Explanation:

The series is bcaa/bcaa/bcaa/bcaa. Thus, the pattern ‘bcaa’ is repeated.