AYBZC, DWEXF, GUHVI, JSKTL, ?
Question: AYBZC, DWEXF, GUHVI, JSKTL, ?
[A].
MQORN
MQNRO
NQMOR
QMONR
[A].
[B].
[C].
[D].
Answer: Option B
Explanation:
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Who among the following are three lady members ?
Question: Who among the following are three lady members ?
[A].E, H and J [B].
E, F and G [C].
E, H and G [D].
C, H and J Answer: Option C
Explanation:
The three lady members are E, H and G.
Flow : River :: Stagnant : ?
Question: Flow : River :: Stagnant : ?
[A].Rain [B].
Stream [C].
Pool [D].
Canal Answer: Option C
Explanation:
As Water of a River flows similarly water of Pool is Stagnant.
8 : 28 :: 27 : ?
Question: 8 : 28 :: 27 : ?
[A].28 [B].
8 [C].
64 [D].
65 Answer: Option D
Explanation:
First number = 8 and the sum of the digits of the second number is 2 + 8 = 10.
Thus the difference of the first number and the sum of the digits of second number is 10 – 8 = 2.
Similarly, the sum of the digits of third number is 2 + 7 = 9.
Hence the sum of digits of fourth number should be 2 more than 9 i.e. 11
Hence, fourth number is 65.
Conference : Chairman :: Newspaper : ?
Question: Conference : Chairman :: Newspaper : ?
[A].Reporter [B].
Distributor [C].
Printer [D].
Editor Answer: Option D
Explanation:
As Chairman is the highest authority in a conference similarly Editor is in Newspaper.
In the following diagram the boys who are athletic and are disciplined are indicated by which number?
Question: In the following diagram the boys who are athletic and are disciplined are indicated by which number?
[A].1 [B].
2 [C].
10 [D].
6 Answer: Option B
Explanation:
The required number is 2.
A bird shooter was askgd how many birds he had in the bag. He replied that there were all sparrows but six, all pigeons but six, and all ducks but six. How many birds he had in the bag in all?
Question: A bird shooter was askgd how many birds he had in the bag. He replied that there were all sparrows but six, all pigeons but six, and all ducks but six. How many birds he had in the bag in all?
[A].9 [B].
18 [C].
27 [D].
36 Answer: Option A
Explanation:
There were all sparrows but six’ means that six birds were not sparrows but only pigeons and ducks.
Similarly, number of sparrows + number of ducks = 6 and number of sparrows + number of pigeons = 6.
This is possible when there are 3 sparrows, 3 pigeons and 3 ducks i.e. 9 birds in all.