[A].
[B].
[C].
[D].
Answer: Option B
Explanation:
| Speed = | 54 x | 5 | m/sec = 15 m/sec. | |
| 18 |
Length of the train = (15 x 20)m = 300 m.
Let the length of the platform be x metres.
| Then, | x + 300 | = 15 |
| 36 |
x + 300 = 540
x = 240 m.
[B].
[C].
[D].
Answer: Option B
Explanation:
| Speed = | 54 x | 5 | m/sec = 15 m/sec. | |
| 18 |
Length of the train = (15 x 20)m = 300 m.
Let the length of the platform be x metres.
| Then, | x + 300 | = 15 |
| 36 |
x + 300 = 540
x = 240 m.
[B].
[C].
[D].
Answer: Option D
Explanation:
| Speed = | 72 x | 5 | m/sec | = 20 m/sec. | |
| 18 |
Time = 26 sec.
Let the length of the train be x metres.
| Then, | x + 250 | = 20 |
| 26 |
x + 250 = 520
x = 270.
[B].
[C].
[D].
Answer: Option C
Explanation:
| Speed = | 45 x | 5 | m/sec | = | 25 | m/sec. | ||
| 18 | 2 |
Time = 30 sec.
Let the length of bridge be x metres.
| Then, | 130 + x | = | 25 |
| 30 | 2 |
2(130 + x) = 750
x = 245 m.
Video Explanation: https://youtu.be/M_d8WufJWKc
[B].
[C].
[D].
Answer: Option D
Explanation:
| Speed = | 60 x | 5 | m/sec | = | 50 | m/sec. | ||
| 18 | 3 |
Length of the train = (Speed x Time).
| Length of the train = | 50 | x 9 | m = 150 m. | |
| 3 |
Video Explanation: https://youtu.be/q6Xy5JXNp-k
[B].
[C].
[D].
Answer: Option A
Explanation:
|
Formula for converting from km/hr to m/s: X km/hr = |
X x | 5 | m/s. | ||
| 18 |
| Therefore, Speed = | 45 x | 5 | m/sec | = | 25 | m/sec. | |
| 18 | 2 |
Total distance to be covered = (360 + 140) m = 500 m.
| Formula for finding Time = | Distance | ||
| Speed |
| Required time = | 500 x 2 | sec | = 40 sec. | |
| 25 |
[B].
[C].
[D].
Answer: Option A
Explanation:
Let the numbers be a, b and c.
Then, a2 + b2 + c2 = 138 and (ab + bc + ca) = 131.
(a + b + c)2 = a2 + b2 + c2 + 2(ab + bc + ca) = 138 + 2 x 131 = 400.
(a + b + c) = 400 = 20.
Video Explanation: https://youtu.be/qmJ-0X8j_xQ
[B].
[C].
[D].
Answer: Option B
Explanation:
| Let the ten’s and unit digit be x and | 8 | respectively. |
| x |
| Then, | 10x + | 8 | + 18 = 10 x | 8 | + x | ||
| x | x |
10×2 + 8 + 18x = 80 + x2
9×2 + 18x – 72 = 0
x2 + 2x – 8 = 0
(x + 4)(x – 2) = 0
x = 2.
[B].
[C].
[D].
Answer: Option B
Explanation:
Let the middle digit be x.
Then, 2x = 10 or x = 5. So, the number is either 253 or 352.
Since the number increases on reversing the digits, so the hundred’s digits is smaller than the unit’s digit.
Hence, required number = 253.
[B].
[C].
[D].
Answer: Option B
Explanation:
Since the number is greater than the number obtained on reversing the digits, so the ten’s digit is greater than the unit’s digit.
Let ten’s and unit’s digits be 2x and x respectively.
Then, (10 x 2x + x) – (10x + 2x) = 36
9x = 36
x = 4.
Required difference = (2x + x) – (2x – x) = 2x = 8.
[B].
[C].
[D].
Answer: Option B
Explanation:
Let the ten’s digit be x and unit’s digit be y.
Then, (10x + y) – (10y + x) = 36
9(x – y) = 36
x – y = 4.
Video Explanation: https://youtu.be/7QOJjAmGVx0