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A shopkeeper expects a gain of 22.5% on his cost price. If in a week, his sale was of Rs. 392, what was his profit?

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Question: A shopkeeper expects a gain of 22.5% on his cost price. If in a week, his sale was of Rs. 392, what was his profit?
[A].

Rs. 18.20

[B].

Rs. 70

[C].

Rs. 72

[D].

Rs. 88.25

Answer: Option C

Explanation:

C.P. = Rs. 100 x 392 = Rs. 1000 x 392 = Rs. 320
122.5 1225

Profit = Rs. (392 – 320) = Rs. 72.

Video Explanation: https://youtu.be/a36nJFgh5yk

100 oranges are bought at the rate of Rs. 350 and sold at the rate of Rs. 48 per dozen. The percentage of profit or loss is:

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Question: 100 oranges are bought at the rate of Rs. 350 and sold at the rate of Rs. 48 per dozen. The percentage of profit or loss is:
[A].

14 2 % gain
7

[B].

15% gain

[C].

14 2 % loss
7

[D].

15 % loss

Answer: Option A

Explanation:

C.P. of 1 orange = Rs. 350 = Rs. 3.50
100
S.P. of 1 orange = Rs. 48 = Rs. 4
12
Gain% = 0.50 x 100 % = 100 % = 14 2 %
3.50 7 7

Sam purchased 20 dozens of toys at the rate of Rs. 375 per dozen. He sold each one of them at the rate of Rs. 33. What was his percentage profit?

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Question: Sam purchased 20 dozens of toys at the rate of Rs. 375 per dozen. He sold each one of them at the rate of Rs. 33. What was his percentage profit?
[A].

3.5

[B].

4.5

[C].

5.6

[D].

6.5

Answer: Option C

Explanation:

Cost Price of 1 toy = Rs. 375 = Rs. 31.25
12

Selling Price of 1 toy = Rs. 33

So, Gain = Rs. (33 – 31.25) = Rs. 1.75

Profit % = 1.75 x 100 % = 28 % = 5.6%
31.25 5

Video Explanation: https://youtu.be/MhswuvDVWzo

Alfred buys an old scooter for Rs. 4700 and spends Rs. 800 on its repairs. If he sells the scooter for Rs. 5800, his gain percent is:

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Question: Alfred buys an old scooter for Rs. 4700 and spends Rs. 800 on its repairs. If he sells the scooter for Rs. 5800, his gain percent is:
[A].

4 4 %
7

[B].

5 5 %
11

[C].

10%

[D].

12%

Answer: Option B

Explanation:

Cost Price (C.P.) = Rs. (4700 + 800) = Rs. 5500.

Selling Price (S.P.) = Rs. 5800.

Gain = (S.P.) – (C.P.) = Rs.(5800 – 5500) = Rs. 300.

Gain % = 300 x 100 % = 5 5 %
5500 11

Two, trains, one from Howrah to Patna and the other from Patna to Howrah, start simultaneously. After they meet, the trains reach their destinations after 9 hours and 16 hours respectively. The ratio of their speeds is:

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Question: Two, trains, one from Howrah to Patna and the other from Patna to Howrah, start simultaneously. After they meet, the trains reach their destinations after 9 hours and 16 hours respectively. The ratio of their speeds is:
[A].

2 : 3

[B].

4 : 3

[C].

6 : 7

[D].

9 : 16

Answer: Option B

Explanation:

Let us name the trains as A and B. Then,

(A’s speed) : (B’s speed) = b : a = 16 : 9 = 4 : 3.

Two stations A and B are 110 km apart on a straight line. One train starts from A at 7 a.m. and travels towards B at 20 kmph. Another train starts from B at 8 a.m. and travels towards A at a speed of 25 kmph. At what time will they meet?

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Question: Two stations A and B are 110 km apart on a straight line. One train starts from A at 7 a.m. and travels towards B at 20 kmph. Another train starts from B at 8 a.m. and travels towards A at a speed of 25 kmph. At what time will they meet?
[A].

9 a.m.

[B].

10 a.m.

[C].

10.30 a.m.

[D].

11 a.m.

Answer: Option B

Explanation:

Suppose they meet x hours after 7 a.m.

Distance covered by A in x hours = 20x km.

Distance covered by B in (x – 1) hours = 25(x – 1) km.

20x + 25(x – 1) = 110

45x = 135

x = 3.

So, they meet at 10 a.m.

A train travelling at 48 kmph completely crosses another train having half its length and travelling in opposite direction at 42 kmph, in 12 seconds. It also passes a railway platform in 45 seconds. The length of the platform is

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Question: A train travelling at 48 kmph completely crosses another train having half its length and travelling in opposite direction at 42 kmph, in 12 seconds. It also passes a railway platform in 45 seconds. The length of the platform is
[A].

400 m

[B].

450 m

[C].

560 m

[D].

600 m

Answer: Option A

Explanation:

Let the length of the first train be x metres.

Then, the length of the second train is x metres.
2
Relative speed = (48 + 42) kmph = 90 x 5 m/sec = 25 m/sec.
18
[x + (x/2)] = 12 or 3x = 300     or     x = 200.
25 2

Length of first train = 200 m.

Let the length of platform be y metres.

Speed of the first train = 48 x 5 m/sec = 40 m/sec.
18 3
(200 + y) x 3 = 45
40

600 + 3y = 1800

y = 400 m.

A train overtakes two persons walking along a railway track. The first one walks at 4.5 km/hr. The other one walks at 5.4 km/hr. The train needs 8.4 and 8.5 seconds respectively to overtake them. What is the speed of the train if both the persons are walking in the same direction as the train?

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Question: A train overtakes two persons walking along a railway track. The first one walks at 4.5 km/hr. The other one walks at 5.4 km/hr. The train needs 8.4 and 8.5 seconds respectively to overtake them. What is the speed of the train if both the persons are walking in the same direction as the train?
[A].

66 km/hr

[B].

72 km/hr

[C].

78 km/hr

[D].

81 km/hr

Answer: Option D

Explanation:

4.5 km/hr = 4.5 x 5 m/sec = 5 m/sec = 1.25 m/sec, and
18 4
5.4 km/hr = 5.4 x 5 m/sec = 3 m/sec = 1.5 m/sec.
18 2

Let the speed of the train be x m/sec.

Then, (x – 1.25) x 8.4 = (x – 1.5) x 8.5

8.4x – 10.5 = 8.5x – 12.75

0.1x = 2.25

x = 22.5

Speed of the train = 22.5 x 18 km/hr = 81 km/hr.
5

A train overtakes two persons who are walking in the same direction in which the train is going, at the rate of 2 kmph and 4 kmph and passes them completely in 9 and 10 seconds respectively. The length of the train is:

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Question: A train overtakes two persons who are walking in the same direction in which the train is going, at the rate of 2 kmph and 4 kmph and passes them completely in 9 and 10 seconds respectively. The length of the train is:
[A].

45 m

[B].

50 m

[C].

54 m

[D].

72 m

Answer: Option B

Explanation:

2 kmph = 2 x 5 m/sec = 5 m/sec.
18 9
4 kmph = 4 x 5 m/sec = 10 m/sec.
18 9

Let the length of the train be x metres and its speed by y m/sec.

Then, x = 9 and x = 10.
y – 5
9
y – 10
9

9y – 5 = x and 10(9y – 10) = 9x

9y – x = 5 and 90y – 9x = 100.

On solving, we get: x = 50.

Length of the train is 50 m.