[A].
[B].
[C].
[D].
Answer: Option C
Explanation:
Let the principal be P and rate of interest be R%.
| Required ratio = |
|
= | 6PR | = | 6 | = 2 : 3. | ||||
|
9PR | 9 |
Video Explanation: https://youtu.be/GaaEDwTWc6w
[B].
[C].
[D].
Answer: Option C
Explanation:
Let the principal be P and rate of interest be R%.
| Required ratio = |
|
= | 6PR | = | 6 | = 2 : 3. | ||||
|
9PR | 9 |
Video Explanation: https://youtu.be/GaaEDwTWc6w
[B].
[C].
[D].
Answer: Option D
Explanation:
We need to know the S.I., principal and time to find the rate.
Since the principal is not given, so data is inadequate.
[B].
[C].
[D].
Answer: Option D
Explanation:
| Principal |
|
|||||
|
||||||
| = Rs. 8925. |
[B].
[C].
[D].
Answer: Option C
Explanation:
| Principal = Rs. | 100 x 5400 | = Rs. 15000. | ||
| 12 x 3 |
[B].
[C].
[D].
Answer: Option B
Explanation:
Let rate = R% and time = R years.
| Then, | 1200 x R x R | = 432 | ||
| 100 |
12R2 = 432
R2 = 36
R = 6.
Video Explanation: https://youtu.be/TjjI4iRkzT0
[B].
[C].
[D].
Answer: Option D
Explanation:
S.I. = Rs. (15500 – 12500) = Rs. 3000.
| Rate = | 100 x 3000 | % | = 6% | |
| 12500 x 4 |
Video Explanation: https://youtu.be/SIcQu1HOmOk
[B].
[C].
[D].
Answer: Option B
Explanation:
| Time = | 100 x 81 | years | = 4 years. | |
| 450 x 4.5 |
Video Explanation: https://youtu.be/WdBzN0Sj8jc
[B].
[C].
[D].
Answer: Option A
Explanation:
| Gain in 2 years |
|
||||||||||||||||
| = Rs. (625 – 400) | |||||||||||||||||
| = Rs. 225. |
| Gain in 1 year = Rs. | 225 | = Rs. 112.50 | ||
| 2 |
Video Explanation: https://youtu.be/zBjcwqIcmL4
[B].
[C].
[D].
Answer: Option B
Explanation:
Let the fourth proportional to 5, 8, 15 be x.
Then, 5 : 8 : 15 : x
5x = (8 x 15)
| x = | (8 x 15) | = 24. |
| 5 |
[B].
[C].
[D].
Answer: Option D
Explanation:
| Quantity of milk = | 60 x | 2 | litres = 40 litres. | |
| 3 |
Quantity of water in it = (60- 40) litres = 20 litres.
New ratio = 1 : 2
Let quantity of water to be added further be x litres.
| Then, milk : water = | 40 | . | ||
| 20 + x |
| Now, | 40 | = | 1 | ||
| 20 + x | 2 |
20 + x = 80
x = 60.
Quantity of water to be added = 60 litres.