An officer was appointed on maximum daily wages on contract money of Rs. 4956. But on being absent for some days, he was paid only Rs. 3894. For how many days was he absent?
A. 3
B. 4
C. 5
D. 6
HCF of 4956, 3894 = 354
(4956 – 3894)/354 = 3
A. 3
B. 4
C. 5
D. 6
HCF of 4956, 3894 = 354
(4956 – 3894)/354 = 3
A. Rs. 110
B. Rs. 120
C. Rs. 125
D. Rs. 150
Explanation:
125% of 120% of A = 225
125/100 * 120/100 * A = 225
A = 225 * 2/3 = 150.
A. 133.33 kmph
B. 1.33 kmph
C. 4 kmph
D. 8 kmph
He crosses 0.4 km in 3/60th of an hour. Speed = 0.4/(1/20) = 8 kmph
A. Rs.4000
B. Rs.1000
C. Rs.1250
D. Rs.2000
Explanation:
P(11/10)4 – P(6/5)2 = 482
P = 2000
A. 10 min
B. 11 min 20 sec
C. 13 min
D. 13 min 20 sec
Speed = (10 X 60/12 ) km/hr = 50 km/hr. New speed = (50 – 5) km / hr = 45 km /hr. So Time taken = ( 10/45 ) hr = ( 2/9X 60 )min 131/3 min = 13 min 20 sec.
A. 4 years
B. 6 years
C. 2 years
D. 3 years
Explanation:
9261 = 8000(21/20)N
(21/20)3 = (21/20)N => N = 3
A. 4
B. 5
C. 6
D. -4
E. None of these
Explanation:
9 x + x = 13 + 27
10 x = 40 => x = 4