interest Mcqs | Mathematics Mcqs

A sum of Rs. 12,500 amounts to Rs. 15,500 in 4 years at the rate of simple interest What is the rate of interest ?

Byadmin February 3, 2020July 25, 2021

A sum of Rs. 12,500 amounts to Rs. 15,500 in 4 years at the rate of simple interest What is the rate of interest ?

A. 3%
B. 4%
C. 5%
D. 6%
S.I. = Rs. (15500 – 12500) = Rs. 3000.
Rate = ( 100 X 3000/12500 X 4 )% = 6%.

Compound Interest | Mathematics Mcqs

If Rs.7500 are borrowed at C.I at the rate of 4% per annum, then after 2 years the amount to be paid is_______?

If Rs.7500 are borrowed at C.I at the rate of 4% per annum, then after 2 years the amount to be paid is_______?

A. Rs.8082
B. Rs.7800
C. Rs.8100
D. Rs.8112
Explanation:
A = 7500(26/25)2 = 8112

Read More If Rs.7500 are borrowed at C.I at the rate of 4% per annum, then after 2 years the amount to be paid is_______?
Mathematics Mcqs | Profit and Loss Mcqs

A man sold two houses for Rs. 7.8 lakhs each. On the one, he gained 5% and on the other, he lost 5%. What percent is the effect of the sale on the whole?

A man sold two houses for Rs. 7.8 lakhs each. On the one, he gained 5% and on the other, he lost 5%. What percent is the effect of the sale on the whole?

A. 0.25 % loss
B. 0.25 % gain
C. 25% loss
D. 25% gain
Explanation:
Loss% = (5/10)2 = ¼% = 0.25%

Read More A man sold two houses for Rs. 7.8 lakhs each. On the one, he gained 5% and on the other, he lost 5%. What percent is the effect of the sale on the whole?
Mathematics Mcqs | Problems on L.C.M and H.C.F

A merchant has three different types of milk: 435 liters, 493 liters and 551 liters. Find the least number of casks of equal size required to store all the milk without mixing.

A merchant has three different types of milk: 435 liters, 493 liters and 551 liters. Find the least number of casks of equal size required to store all the milk without mixing.

A. 51
B. 61
C. 47
D. 45
Explanation:
HCF of 435, 493, 551 = 29
(453/29) + (493/29) + (551/29) = 51

Read More A merchant has three different types of milk: 435 liters, 493 liters and 551 liters. Find the least number of casks of equal size required to store all the milk without mixing.
Compound Interest | Mathematics Mcqs

Find the sum The difference between the compound and S.I. on a certain sum of money for 2 years at 10% per annum is Rs.15of money?

Find the sum The difference between the compound and S.I. on a certain sum of money for 2 years at 10% per annum is Rs.15of money?

A. 1500
B. 1800
C. 2100
D. 1950
P = 15(100/10)2 => P = 1500

Read More Find the sum The difference between the compound and S.I. on a certain sum of money for 2 years at 10% per annum is Rs.15of money?
Areas | Mathematics Mcqs

If the length and width of a rectangular grand are each increased by 20% then what would be the percent increase in the area of the garden?

If the length and width of a rectangular grand are each increased by 20% then what would be the percent increase in the area of the garden?

A. 20%
B. 24%
C. 36%
D. 44%

Let length = x metres and breadth = y metres , then area =(xy)m2
New length = 120/100x (6x/5)m
New breadth = 120/100 y = 6y/5m
New area (6x/5 x 6y/5)m2 = (36/25 xy)m2
Increase in area = (36/25xy – xy)m2 = (11/25 xy)m2
Increase % = (11/25 xy x 1/xy x 100)% = 44%

Read More If the length and width of a rectangular grand are each increased by 20% then what would be the percent increase in the area of the garden?
Mathematics Mcqs | Time & Distance Mcqs

A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of

A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of

A. 120
B. 260
C. 240
D. 220

Explanation with best method.
5 Steps
1.Data:
Train station platform= 36Sec
Standing platform = 20Sec
Speed of train = 54km/hr
2.Required:
Length of platform= x=???
3.Formula:
X+length of train/Train station platform
4.Solution: first for terms
Speed = 54 ×1000m/3600sec = 15 m/Sec.
Length of the train = (15 m/Sec × 20Sec = 300 m.
Let the length of the platform be x metres.
Now, x + 300m /36Sec= 15 m/Sec
x+300m= 15m/Sec×36Sec
x + 300m = 540m
x= 540m-300m
x = 240 m.
5.Result:
Length of platform=x=240m

Read More A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of

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