A. 15%
B. 10%
C. 7 1/2 %
D. 8%
A. 65%
B. 70%
C. 80%
D. 60%
Explanation:
Total area =(30 x 15)Sq.cm =45 Sq.cm
Area used =[(30 – 1.25 x 2) x (15 -2.5 x2)]
=(27.5 x 10)Sq.cm =275 Sq.cm
Percentage of area used =(275/450 x 100)% =61.1%
= 60%(Approx.)
A. 8% p.a.
B. 6% p.a.
C. 4% p.a.
D. 5% p.a.
E. None of these
Explanation:
Let the rate of interest be R% p.a.
17400[1 + R/100]2 = 17400 + 1783.50
[1 + R/100]2 = (17400 + 1783.50)/17400
= 1 + 1025/10000 = 1 + 41/400
= 441/400 = [21/20]2
[1 + R/100] = 21/20
R/100 = 1/20
Therefore R = 5
A. -2, -1/2
B. 4, -1
C. 4, 1
D. -2, 5/2
Explanation:
2×2 + 4x + x + 2 = 0
2x(x + 2) + 1(x + 2) = 0
(x + 2)(2x + 1) = 0 => x = -2, -1/2
A. If x < y
B. If x > y
C. If x ≤ y
D. If x ≥ y
E. If x = y or the relationship between x and y cannot be established.
Explanation:
I. x2 + 6x – 3x – 18 = 0
=>(x + 6)(x – 3) = 0 => x = -6, 3
II. y2 + 6y – 5y – 30 = 0
=>(y + 6)(y – 5) = 0 => y = -6, 5
No relationship can be established between x and y.
A. 3 hrs 15 min
B. 3 hrs 45 min
C. 4 hrs
D. 4 hrs 15 min
Explanation:
Time taken by one tap to fill the tank = 3 hrs.
Part filled by the taps in 1 hour = 4 * 1/6 = 2/3
Remaining part = 1 – 1/2 = 1/2
2/3 : 1/2 :: 1 : x
x = 1/2 * 1 * 3/2 = 3/4 hrs. i.e., 45 min
So, total time taken = 3 hrs 45 min.
A. 9
B. 10
C. 12
D. 20
Due to stoppages, the bus travels only 45 kms in an hour (9 kms less). To cover a distance of 9 km at a speed of 54 kmph, time taken
= 9/54 = 1/6 hrs = 10 mins.