A stone is thrown upward from the top of a 59.4m high cliff with an upward velocity component of 19.6m/s how long is the stone in the air?A. 4.00 s
B. 5.00 s
C. 6.00 s
D. 7.00 s
B. 5.00 s
C. 6.00 s
D. 7.00 s
Applying newtons formula,
S= ut + (1/2)at^2
Let downwards direction be (-) be
, so
-59.4 = 19.5t – (1/2) 10t^2
By Sloving this you will get ,t= 6 sec