A. Rs.5
B. Rs.4
C. Rs.2
D. Rs.3
Explanation:
40*(40/100) = 16 — 64
? — 12 => Rs.3
A. Rs. 12
B. Rs. 12.96
C. Rs. 14.40
D. None of these
Explanation:
90 : 10.80 :: 120 : x
X = (10.80 ×120)/90 = 14.40
Hence, the toy must be sold for Rs. 14.40
A. Rs. 7500
B. Rs. 9000
C. Rs. 9500
D. Rs. 10,000
E. None of these
Explanation:
A:B:C = (20000 * 24) : (15000 * 24) : (20000 * 18) = 4:3:3
B’s = 25000 * 3/10 = Rs. 7500.
A. 7.5m
B. 8.5m
C. 10.5m
D. 12.5m
A. 0
B. 1
C. 10
D. 19
Average of 20 numbers = 0
Sum of 20 numbers = (0 * 20) = 0
It is quite possible that 19 of these numbers may be positive and if their sum is a, then 20th number is (-a).
A. 24
B. 48
C. 56
D. 60
Explanation:
H.C.F of two numbers divides their L.C.M exactly. Clearly, 8 is not a factor of 60.
A. Rs.10,840
B. Rs.10,720
C. Rs.10,560
D. Rs.10,280
E. None of these.
Explanation:
Let the rate of interest be R% p.a.
4400{[1 + R/100]2 – 1} = 11193.60
[1 + R/100]2 = (44000 + 11193.60)/44000
[1 + R/100]2 = 1 + 2544/1000 = 1 + 159/625
[1 + R/100]2 = 784/625 = (28/25)2
1 + R/100 = 28/25
R/100 = 3/25
Therefore R = 12 SI on Rs.44000 at 12% p.a. for two years = 44000(2)(12)/100
=Rs.10560