A. Rs. 15
B. Rs. 12
C. Rs. 10
D. Rs. 8
A. 300 km
B. 290 km
C. 250 km
D. 240 km
Total distance = (120*2) + (100*(1/2)) = 290 km
A. 15
B. 18
C. 24
D. 30
Explanation:
Case I : 2 balls of the same colour and two balls are a different colour are arranged.
Two balls of the same colour and two balls of different colours can be arranged together in which two balls of the same colour are adjacent =4!/2!x2! = 6 ways
Therefore, Total number of arrangements = 6×3 =18 ways
Case II : Two colours out of 3 can be selected in = 3C1 = 3ways
Now 2 balls of each colour can be arranged alternatively in 2 ways
Thus 4 balls can be arranged(two of each colours)
= 3×2 = 6ways
Hence total number of arrangements = 18+6 =24 ways
A. Rs.3
B. Rs.4.50
C. Rs.5.00
D. Rs.7.50
2: 5: 13
2x 5x 13x
15 7.5 2.5
30x + 37.5x + 32.5x = 100x/20x
Average = 5
A. 13/51
B. 1/17
C. 1/26
D. 13/17
A. -6, 7
B. -8, 7
C. 14, -3
D. -7, 6
Explanation:
x2 + 7x – 6x + 42 = 0
x(x + 7) – 6(x + 7) = 0
(x + 7)(x – 6) = 0 => x = -7, 6
A. 120
B. 240
C. 360
D. 480
Explanation:
2 24 – 36 – 40
——————–
2 12 – 18 – 20
——————–
2 6 – 9 – 10
——————-
3 3 – 9 – 5
——————–
1 – 3 – 5
L.C.M = 2 * 2 * 2 * 3 * 3 * 5 = 360.