A. 2 3/2
B. 2 2/3
C. 2.5
D. 3
Explanation:
100*(20/100) = 20 — 10
? — 1 => Rs.2
100 — 80
? — 2 => Rs.2.5
A. 18 3/4 %
B. 20 %
C. 16 3/4 %
D. 19 %
Explanation:
Required % = (9/48 × 100)% = 75/4 % = 18 ¾ %
A. 167
B. 154
C. 162
D. 181
Explanation:
(3.32/100 * 2113) * 1/42 = (70.1516) * 1/42 = 167
A. 45 cm
B. 40 cm
C. 36 cm
D. 27 cm
Let the three sides be 4x,3x and 2x. 4x+3x+2x = 81 9x = 81 x = 9 Length of the largest side
= 4x = 36 cm
A. 91.5 cm
B. 93.5 cm
C. 94.5 cm
D. 92.5 cm
Perimeter of the sector = length of the arc + 2(radius)
= (135/360 * 2 * 22/7 * 21) + 2(21)
= 49.5 + 42 = 91.5 cm
A. 75
B. 150
C. 50
D. None of these
Let the marks obtained by the student in Physics, Chemistry and Mathematics be P, C and M respectively.
P + C + M = 150 + P
C + M = 150
Average mark obtained by the student in Chemistry and Mathematics = (C + M)/2 = 150/2 = 75
A. 48
B. 34(2/7)
C. 44
D. 45
(1/A)+(1/B) = (1/20) (1/B)+(1/C) = (1/30) (1/A)+(1/C) = (1/40) Solving the three equations,
A=48