A rectangular park 60 m long and 40 m wide has two concrete crossroads running in the middle of the park and rest of the park has been used as a lawn. If the area of the lawn is 2109 sq. m, then what is the width of the road?

Question: A rectangular park 60 m long and 40 m wide has two concrete crossroads running in the middle of the park and rest of the park has been used as a lawn. If the area of the lawn is 2109 sq. m, then what is the width of the road?
[A].

2.91 m

[B].

3 m

[C].

5.82 m

[D].

None of these

Answer: Option B

Explanation:

Area of the park = (60 x 40) m2 = 2400 m2.

Area of the lawn = 2109 m2.

Area of the crossroads = (2400 – 2109) m2 = 291 m2.

Let the width of the road be x metres. Then,

60x + 40x – x2 = 291

x2 – 100x + 291 = 0

(x – 97)(x – 3) = 0

x = 3.

Video Explanation: https://youtu.be/R3CtrAKGxkc