A. 12 m, 10 m
B. 13 m, 12 m
C. 14 m, 11 m
D. 15 m, 10 m
A. 1400
B. 1300
C. 1200
D. 1100
Explanation:
CP* (76/100) = 912
CP= 12 * 100 => CP = 1200
A. 24 cm3
B. 48 cm3
C. 64 cm3
D. 120 cm3
Let the dimensions of the cuboid be x, 2x and 3x.
Then, 2 (x X 2x + 2x X 3x + x X 3x) = 88
⇔ 2X2 6X2 + 3X2 = 44 ⇔ 11X2 = 44 ⇔ X2 = 4 ⇔ x = 2.
Volume of the Cuboid = (2 X 4 X 6) cm3 = 48 cm3.
A. 1/21
B. 4/7
C. 2/7
D. 5/7
A. 10/17
B. 10/19
C. 46/105
D. Cannot be determined
Explanation:
There is no definite formula for finding prime numbers among 15 consecutive numbers. Hence the probability cannot be determined.
A. Rs.1104
B. Rs.1000
C. Rs.934
D. Rs.1210
Assume that cost of keeg a cow for 1 day = c ,
cost of keeg a goat for 1 day = g
Cost of keeg 20 cows and 40 goats for 10 days = 460
Cost of keeg 20 cows and 40 goats for 1 day = 460/10 = 46
=> 20c + 40g = 46
=> 10c + 20g = 23 —(1)
Given that 5g = c
Hence equation (1) can be written as 10c + 4c = 23 => 14c =23
=> c=23/14
cost of keeg 50 cows and 30 goats for 1 day
= 50c + 30g
= 50c + 6c (substituted 5g = c)
= 56 c = 56×23/14
= 92
Cost of keeg 50 cows and 30 goats for 12 days = 12×92 = 1104
A. 11
B. 30
C. 14
D. 20
Explanation:
For each visualization let us name the females and Females(3) Males(5)
A B C D E F G H
Since A cannot go with B.
She will make team with four males in four ways AD,AF,AG,AH.
Since there is no compulsion with females C and E.
They can make team with 5 males in 5 different ways each.
Therefore, Total number of ways = 4+5+5 =14