A person crosses a 600 m long street in 5 minutes. What is his speed in km per hour?
A person crosses a 600 m long street in 5 minutes. What is his speed in km per hour?
A. 8.2
B. 4.2
C. 6.1
D. 7.2
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4 singers, 5 dancers and 3 comperes divide an amount of Rs.130000 among themselves such that 3 comperes get as much as 2 dancers and 3 dancers get as much as 2 singers. Find the amount received by a singer.
4 singers, 5 dancers and 3 comperes divide an amount of Rs.130000 among themselves such that 3 comperes get as much as 2 dancers and 3 dancers get as much as 2 singers. Find the amount received by a singer.A. Rs.18000
B. Rs.13000
C. Rs.15000
D. Rs.10000
4S+5D+3C=130000 3C=2D 3D=2S S=3D/2 [4*(3D/2)]+5D+2D = 130000 6D+5D+2D = 130000 13D = 130000 D = Rs.10000 S=3D/2 = Rs.15000Twelve men can do a work in twenty days while twenty women can finish the same work in sixteen days. Find the ratio between the capacity of a man and a woman.
Twelve men can do a work in twenty days while twenty women can finish the same work in sixteen days. Find the ratio between the capacity of a man and a woman.A. 3:4
B. 5:4
C. 4:3
D. 5:3
Part of work completed by a man in a day = 1/(12*20)
= 1/240 Part of work completed by a woman in a day = 1/(20*16) = 1/320 Ratio of their capacities
= (1/240):(1/320) = 320:240 = 4:3I. a2 – 13a + 42 = 0, II. b2 – 15b + 56 = 0 to solve both the equations to find the values of a and b?
I. a2 – 13a + 42 = 0,
II. b2 – 15b + 56 = 0 to solve both the equations to find the values of a and b?A. If a > b
B. If a ≥ b
C. If a < b
D. If a ≤ b.
Explanation:
I. a2 – 13a + 42 = 0
=>(a – 6)(a – 7) = 0 => a = 6, 7
II. b2 – 15b + 56 = 0
=>(b – 7)(b – 8) = 0 => b = 7, 8
=>a ≤ bFind the area of trapezium whose parallel sides are 20 cm and 18 cm long, and the distance between them is 15 cm.
Find the area of trapezium whose parallel sides are 20 cm and 18 cm long, and the distance between them is 15 cm.A. 225 cm2
B. 275 cm2
C. 285 cm2
D. 315 cm2
Area of a trapezium = 1/2 (sum of parallel sides) * (perpendicular distance between them) = 1/2 (20 + 18) * (15) = 285 cm2A man buys 10 articles for Rs. 8 and Sells them at the rate of Rs. 1.25 per article. His gain is:________?
A man buys 10 articles for Rs. 8 and Sells them at the rate of Rs. 1.25 per article. His gain is:________?A. 20%
B. 50%
C. 19 ½ %
D. 56 ¼ %
Explanation:
C.P of 10 articles = Rs. 8
S.P of 10 articles = Rs. (1.25 × 10) = Rs. 12.50
Gain = (4.5/8 × 100)% = 56 ¼%The compound interest on a certain sum of money for 2 years at 10 % per annum is Rs.420. The simple interest on the same sum at the same rate and for the same time will be_______?
The compound interest on a certain sum of money for 2 years at 10 % per annum is Rs.420. The simple interest on the same sum at the same rate and for the same time will be_______?A. Rs.350
B. Rs.375
C. Rs. 380
D. Rs. 400
Explanation:
The principle is P.
P(1 +10/100)2 – P = 420
=> P = Rs.2000
S.I = Rs.(4000/100) = Rs.400