A jar full of whisky contains 40% alcohol. A part of this whisky is replaced by another containing 19% alcohol and now the percentage of alcohol was found to be 26%. The quantity of whisky replaced is:
Question:
A jar full of whisky contains 40% alcohol. A part of this whisky is replaced by another containing 19% alcohol and now the percentage of alcohol was found to be 26%. The quantity of whisky replaced is:
[A].
A jar full of whisky contains 40% alcohol. A part of this whisky is replaced by another containing 19% alcohol and now the percentage of alcohol was found to be 26%. The quantity of whisky replaced is:
[A].
| 1 |
| 3 |
[B].
| 2 |
| 3 |
[C].
| 2 |
| 5 |
[D].
| 3 |
| 5 |
Answer: Option B
Explanation:
By the rule of alligation, we have:
|
Strength of first jar Strength of 2nd jar |
||
| 40% | Mean Strength 26% |
19% |
| 7 | 14 | |
So, ratio of 1st and 2nd quantities = 7 : 14 = 1 : 2
| Required quantity replaced = | 2 |
| 3 |