A garrison has sufficient food for 500 people to survive for 6 days. At the end of 2 days 100 men desert. How long the provisions are sufficient for now?
		A. 5
B. 6
C. 4
D. 10
		A. 5
B. 6
C. 4
D. 10
		A. 150 m
B. 125 m
C. 130 m
D. 100 m
Explanation:
A can give B (5 min – 4 1/2 min) = 30 sec start.
The distance covered by B in 5 min = 1000 m.
Distance covered in 30 sec = (1000 * 30)/300 = 100 m.
A can give B 100m start.
		A. 120 km
B. 100 km
C. 80 km
D. 75 km
Let the speed of the bike be x kmph. Then the speed of the car will be 3x/2 kmph. Time taken by the bike
t1 = 100/x Time taken by the bike
t2 = 100/(3x/2) t1 – t2 = 25/60 (100/x) – (100/(3x/2)) = 5/12 Solving the equation, x = 80 kmph
		A. 13/51
B. 1/17
C. 1/26
D. 13/17
		A. 35 Rs.
B. 40 Rs.
C. 45 Rs.
D. None of these
Ratio of time taken by A and B= 10 : 15 = 2 : 3
Ratio of work done in the same time  = 3:2, So, the money is to be divided among A and B in the ratio 3 : 2
A’s  = Rs. [75×3/5] = Rs.45.
		A. 300
B. 600
C. 750
D. 900
Explanation:
Two men, three women and one child can be selected in ⁴C₂ * ⁶C₃ * ⁵C₁ ways
= (4 * 3)/(2 * 1) * (6 * 5 * 4)/(3 * 2) * 5
= 600 ways.
		A. Rs 1575.20
B. Rs 1600
C. Rs 1625.80
D. Rs 2000
Explanation:
Amount = Rs[10000 × (1 + 4/100) × (1 +5/100) × (1 × 6/100)]
= Rs(1000 × 26/25 × 21/20 × 53/50)
= Rs (57876/5) = Rs 11575.20
C.I = Rs (11575.20 – 10000) = Rs 1575.20