A gardener increases the area of his rectangular garden by increasing its length by 40% and decreasing by 20%. The area of the new garden?
A. Has increase by 20%
B. Has increase by 12%
C. Has increase b 8%
D. Is exactly the same as the old area
A. Has increase by 20%
B. Has increase by 12%
C. Has increase b 8%
D. Is exactly the same as the old area
A. 1/21
B. 4/7
C. 2/7
D. 5/7
A. 10 km
B. 8 km
C. 12 km
D. 9 km
Let the distance covered by walking be x km
the distance covered by running be (20-x) km Time for walking + time for running = 3.5 hours (x/4)+[(20-x)/10]=3.5 Solving,
5x+40-2x = 70
3x=30
x=10km
A. 8 cm
B. 12 cm
C. 14 cm
D. 10 cm
A. 7 months
B. 10 months
C. 9 months
D. 11 months
Explanation:
7*5: 5*x = 7:10
x = 10
A. 1:6
B. 2:3
C. 4:3
D. 6:1
A. No change
B. 8%decrease
C. 16% Decrease
D. 16%increases
Explanation:
let the height be ‘h’ and base = b, then area =(1/2 bh)sq.units
New height =(60 % of h) = (60/100 h) = 3h/5
New base =(140% of b) =(140/100 b) =(76/5)
New area =(1/2 x 7b/5 x 3h/5) Sq.units =(21/50 bh)sq.units
Decrease in area =(1/2bh – 21/50bh)= 4/50 bh
Decrease % =(4/50bh. 2/bh x 100)% =16%