Question: A current 10 sin (200t) A flows through a 5 mH inductance. The expression for voltage is
[A].10 sin (200t + 90°)
10 sin (200t – 90°)
10 sin(1000t + 90°)
10 sin (1000t – 90°)
[A].
[B].
[C].
[D].
Answer: Option D
Explanation:
Z = jXL = jωL = = 1∠90° and V = IXL