Question: A coil of resistance R and inductance L is connected in series with 5 μF capacitor. The source frequency is equal to resonance frequency and circuit current is 0.5 A. Another 5 F capacitor is connected in parallel with the above capacitor. The circuit current will be
[A].0.5 A
more than 0.5 A
less than 0.5 A
0.5 A or less
[A].
[B].
[C].
[D].
Answer: Option C
Explanation:
Since C increases, the circuit will not be in resonance. Therefore, current decreases (In series resonant circuit current is maximum at resonance).