A. 30 km/hr
B. 35 km/hr
C. 25 km/hr
D. 40 km/hr
A. 8/15, 9/13, 6/11
B. 8/15, 6/11, 9/13
C. 9/13, 6/11, 8/15
D. 6/11, 8/15, 9/13
Explanation:
The fractions considered are 8/15 9/13 6/11
To compare them we make the denominators the same. So the fractions are
(8 * 13 * 11)/2145, (9 * 15 * 11)/2145 and (6 * 15 * 13)/2145
1144/2145, 1485/2145 and 1170/2145
so in descending order the fractions will be
1485/2145, 1170/2145 and 1144/2145 i.e., 9/13 , 6/11 , 8/15
A. 600
B. 620
C. 500
D. 520
E. None of these
Explanation:
Let the number of children in the school be x. Since each child gets 2 bananas, total number of bananas = 2x.
2x/(x – 360) = 2 + 2(extra)
=> 2x – 720 = x => x = 720.
A. 3000m
B. 7500m
C. 3750m
D. 7000m
Average speed for Raj is: v = (2*9*10)/(9+10) = 180/19 km/hr = 50/19 m/s
Average speed for Rohit = 12 km/hr = 10/3 m/s
Now, v = d/t
As d is same, v*t = constant.
Let, t be the time taken by Rohit in seconds. Hence, time taken by Raj is (t +600)s
50/19 * (t + 600) = 10/3 * t
150*(t + 600) = 190t
t = 2250s
Let d be the distance between the house and the office
2d = 2250 * 10/3
2d = 7500 m
d = 3750m
A. 76 min
B. 80min
C. 90min
D. 96min
A. 700,400
B. 820,360
C. 800,500
D. 820,369
A. 6
B. 12
C. 18
D. None of these
Let the numbers be 3x, 4x and 6x.
Then, 3x x 4x x 6x = 1944 72×3 = 1944
x3 = 27 ,=> x = 3
∴ Largest number = 6x = 18,