Question: A can finish a work in 18 days and B can do the same work in 15 days. B worked for 10 days and left the job. In how many days, A alone can finish the remaining work?
[A].5
6
8
[A].
[B].
| 5 | 1 |
| 2 |
[C].
[D].
Answer: Option C
Explanation:
| B’s 10 day’s work = | 1 | x 10 | = | 2 | . | ||
| 15 | 3 |
| Remaining work = | 1 – | 2 | = | 1 | . | ||
| 3 | 3 |
| Now, | 1 | work is done by A in 1 day. |
| 18 |
| 1 | work is done by A in | 18 x | 1 | = 6 days. | |||
| 3 | 3 |