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A can contains a mixture of two liquids A and B is the ratio 7 : 5. When 9 litres of mixture are drawn off and the can is filled with B, the ratio of A and B becomes 7 : 9. How many litres of liquid A was contained by the can initially?

Question: A can contains a mixture of two liquids A and B is the ratio 7 : 5. When 9 litres of mixture are drawn off and the can is filled with B, the ratio of A and B becomes 7 : 9. How many litres of liquid A was contained by the can initially?
[A].

10

[B].

20

[C].

21

[D].

25

Answer: Option C

Explanation:

Suppose the can initially contains 7x and 5x of mixtures A and B respectively.

Quantity of A in mixture left = 7x – 7 x 9 litres = 7x – 21  litres.
12 4
Quantity of B in mixture left = 5x – 5 x 9 litres = 5x – 15  litres.
12 4
7x – 21
4
= 7
5x – 15  + 9
4
9
28x – 21 = 7
20x + 21 9

252x – 189 = 140x + 147

112x = 336

x = 3.

So, the can contained 21 litres of A.