Question: A and B can complete a work in 15 days and 10 days respectively. They started doing the work together but after 2 days B had to leave and A alone completed the remaining work. The whole work was completed in :
[A].
8 days |
[B].
10 days |
[C].
12 days |
[D].
15 days |
Answer: Option C
Explanation:
| (A + B)’s 1 day’s work = |
|
1 |
+ |
1 |
|
= |
1 |
. |
| 15 |
10 |
6 |
| Work done by A and B in 2 days = |
|
1 |
x 2 |
|
= |
1 |
. |
| 6 |
3 |
| Remaining work = |
|
1 – |
1 |
|
= |
2 |
. |
| 3 |
3 |
| Now, |
1 |
work is done by A in 1 day. |
| 15 |
|
2 |
work will be done by a in |
|
15 x |
2 |
|
= 10 days. |
| 3 |
3 |
Hence, the total time taken = (10 + 2) = 12 days.
