A. -5, 3
B. 3, 5
C. -3, 5
D. -3, -5
Explanation:
x2 + 5x – 3x – 15 = 0
x(x + 5) – 3(x + 5) = 0
(x – 3)(x + 5) = 0
=> x = 3 or x = -5.
A. 10 min
B. 11 min 20 sec
C. 13 min
D. 13 min 20 sec
Speed = (10 X 60/12 ) km/hr = 50 km/hr. New speed = (50 – 5) km / hr = 45 km /hr. So Time taken = ( 10/45 ) hr = ( 2/9X 60 )min 131/3 min = 13 min 20 sec.
A. Rs. 10,000
B. Rs. 10,800
C. Rs. 14,400
D. Rs. 16,000
For an income of Rs. 12, stock needed = Rs. 100.
For an income of Rs. 1200, stock needed = Rs.( 100/12 X 1200 ) = Rs. 10,000.
A. 1.4 m
B. 2.8 m
C. 14 m
D. None of these
A. 9654
B. 9666
C. 9664
D. 9864
A. 5days
B. 6days
C. 7days
D. 8days
Explanation:
Let us assume that Arun uses X units of petrol everyday.
So the amount of petrol in the tank when it is fuel will be 10X.
If he started using 25% more petrol every day, then the amount of petrol he how uses everyday will be
X (1 +25/100) =1.25x
Therefore, number of days his petrol will how last = Amount of petrol in tank / amount of petrol used everyday = 10x/1.25x = 10/1.25 = 8 Days
A. Rs. 2.50
B. Rs. 3
C. Rs. 3.75
D. Rs. 4