A. 4920 cm2
B. 4727 cm2
C. 9856 cm2
D. 19712 cm2
A. 20%
B. 25%
C. 18%
D. 30%
Explanation:
SP = CP + g
150 SP = 150 CP + 30 SP
120 SP = 150 CP
120 — 30 CP
100 — ? => 25%
A. Rs. 9423
B. Rs. 10,250
C. Rs. 12,500
D. Rs. 14,000
E. None of these
Explanation:
Simran : Nanda = (50000 * 36) : (80000 * 30) = 3:4
Simran’s = 24500 * 3/7 = Rs. 10500
A. 8
B. 6
C. 4
D. 2
Explanation:
Let n erasers be available for a rupee
Reduced Price = (75/100 × 1) = Re ¾
¾ rupee fetch n erasers = 1 Rupee will fetch (n × 4/3) erasers
Therefore, 4n/3 = n +2 => 4n = 3n +6 => n =6
A. 10
B. 8
C. 18
D. 19
Let work done by P in 1 day = p,
Work done by Q in 1 day = q,
Work done by R in 1 day = r
p + q = 1/30
q + r = 1/24
r + p = 1/20
Adding all the above, 2p + 2q + 2r = 1/30 + 1/24+ 1/20 = 15/120 = 1/8
=> p + q + r = 1/16
=> Work done by P,Q and R in 1 day = 1/16
Work done by P, Q and R in 10 days = 10 × (1/16) = 10/16 = 5/8
Remaining work = 1 = 5/8 = 3/8
Work done by P in 1 day = Work done by P,Q and R in 1 day – Work done by Q and R in 1 day
= 1/16 – 1/24 = 1/48
Number of days P needs to work to complete the remaining work = (3/8) / (1/48) = 18
A. Rs. 400
B. Rs. 440
C. Rs. 500
D. Rs. 550
Explanation:
Let the C.P. be Rs. x. Then, 20% of x = 1100
20/100 * x = 1100 => x = 5500
C.P. = Rs. 5500, expenditure on repairs = 10%
Actual price = Rs. (100 * 5500)/110 = Rs. 5000
Expenditures on repairs = (5500 – 5000) = Rs. 500.
A. 5 : 3 : 1
B. 5 : 3 : 2
C. 10 : 7 : 4
D. 10 : 8 : 5
E. None of these
Explanation:
Let the prices of X, Y and Z be 8k, 5k and 3k respectively.
After increase
Price of X = 8k * 125/100 = 10k
Price of Y = 5k * 120/100 = 6k
Price of Z = 3k * (133 1/3)/100 = 4k
Required ratio = 10k : 6k : 4k = 5 : 3 : 2.