A. 5 cm
B. 19 cm
C. 13 cm
D. 144 cm
A. Rs. 3944
B. Rs. 3828
C. Rs. 4176
D. None of these
Let the side of the square plot be a ft.
a2 = 289 => a = 17
Length of the fence = Perimeter of the plot = 4a = 68 ft.
Cost of building the fence = 68 * 58 = Rs. 3944.
A. 160m × 27m
B. 240m × 18m
C. 120m × 36m
D. 135m × 32m
Let the side of smaller square at the extreme right be a
Then side of the larger square is 3a
Total area of the field = a2 + a2 +a2 + (3a)2 +(3a)2 = 30a2
Therefore, 30 a2 = 4320 => a2 = 432 / 3 = 144 => a = 12
Smaller side of the field = 36
Larger side of the field = (3a) × 3 + a = 10 a = 10 × 12 = 120
Original Dimensions of the field = 120m × 36m
A. 10
B. 8
C. 18
D. 19
Let work done by P in 1 day = p,
Work done by Q in 1 day = q,
Work done by R in 1 day = r
p + q = 1/30
q + r = 1/24
r + p = 1/20
Adding all the above, 2p + 2q + 2r = 1/30 + 1/24+ 1/20 = 15/120 = 1/8
=> p + q + r = 1/16
=> Work done by P,Q and R in 1 day = 1/16
Work done by P, Q and R in 10 days = 10 × (1/16) = 10/16 = 5/8
Remaining work = 1 = 5/8 = 3/8
Work done by P in 1 day = Work done by P,Q and R in 1 day – Work done by Q and R in 1 day
= 1/16 – 1/24 = 1/48
Number of days P needs to work to complete the remaining work = (3/8) / (1/48) = 18
A. If a > b
B. If a ≥ b
C. If a < b
D. If a ≤ b
Explanation:
a3 = 1331 => a = 11
b2 = 121 => b = ± 11
a ≥ b
A. 49
B. 94
C. 83
D. Either (a) or (b)
E. None of these
Explanation:
Let the number be in the form of 10a + b
Number formed by interchanging a and b = 10b + a.
a + b = 13 — (1)
10b + a = 10a + b – 45
45 = 9a – 9b => a – b = 5 — (2)
Adding (1) and (2), we get
2a = 18 => a = 9 and b = 4
The number is: 94.
A. 600
B. 700
C. 800
D. 900
Explanation:
(40/100) * X – (20/100) * 650 = 190
2/5 X = 320
X = 800