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Find the greatest number that, while dividing 47, 215 and 365, gives the same remainder in each case?

Find the greatest number that, while dividing 47, 215 and 365, gives the same remainder in each case?

A. 3
B. 4
C. 5
D. 6
Explanation:
Calculate the differences, taking two numbers at a time as follows:
(215-47) = 168
(365-215) = 150
(365-47) = 318
HCF of 168, 150 and 318 we get 6, which is the greatest number, which while dividing 47, 215 and 365 gives the same remainder in each cases is 5.