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In finding the HCF of two numbers, the last divisor was 41 and the successive quotients, starting from the first, where 2, 4 and 2. The numbers are______?

/ Mathematics Mcqs, Problems on L.C.M and H.C.F / By
In finding the HCF of two numbers, the last divisor was 41 and the successive quotients, starting from the first, where 2, 4 and 2. The numbers are______?

A. 700,400
B. 820,360
C. 800,500
D. 820,369