In finding the HCF of two numbers, the last divisor was 41 and the successive quotients, starting from the first, where 2, 4 and 2. The numbers are______?
A. 700,400
B. 820,360
C. 800,500
D. 820,369
A. 700,400
B. 820,360
C. 800,500
D. 820,369
A. 10 %
B. 12 %
C. 6 %
D. 8 %
Explanation:
5000 × (1 +R/100) 2 – 5000 –(10000R/100)= 72
=> 5000 [(1 + R/100) 2 – 1 – R/50] = 72
=> 1 + R2/100 + 2R/100 – 1 – R/50 = 72/5000
=> R2 = (72/5000 × 10000) = 144 or R =12%
A. 3
B. 4
C. 5
D. 6
HCF of 4956, 3894 = 354
(4956 – 3894)/354 = 3
A. 6 kmph
B. 7 kmph
C. 8.5 kmph
D. 8 kmph
Explanation:
S = 1
M = x
DS = x + 1
US = x – 1
35/(x + 1) + 35/(x – 1) = 12
x = 6
A. 5 km
B. 5.5 km
C. 6 km
D. 6.5 km
Average speed = ( 2 X 3 X 2/3 + 2 ) km/ hr = 12/5 km/ hr. Distance travelled = ( 12/5 X 5 )km = 12 km. So Distance between house and school = ( 12/2 )km = 6 km.
A. 4920 cm2
B. 4727 cm2
C. 9856 cm2
D. 19712 cm2
A. 25
B. 13
C. 40
D. 30
Explanation:
The word contains five consonants. Three vowels, three consonants can be selected from five consonants in ⁵C₃ ways, two vowels can be selected from three vowels in ³C₂ ways.
3 consonants and 2 vowels can be selected in ⁵C₂ . ³C₂ ways i.e., 10 * 3 = 30 ways.