Two numbers 4242 and 2903 when divided by a certain number of three digits, leave the same remainder. Find the number?
A. 101
B. 103
C. 107
D. 113
A. 101
B. 103
C. 107
D. 113
A. 5
B. 6
C. 7
D. 18
Explanation:
Number of ways of opting a subject other than Mathematics II = 4C2. = 4x3x2!/2!x2 = 6.
Number of ways of selection of Mathematics II = 1
Therefore, Total Number of ways = 6+1 =7.
A. Rs. 12
B. Rs. 12.96
C. Rs. 14.40
D. None of these
Explanation:
90 : 10.80 :: 120 : x
X = (10.80 ×120)/90 = 14.40
Hence, the toy must be sold for Rs. 14.40
A. Rs. 112
B. Rs. 118.80
C. Rs. 120
D. Rs. 122
A. 10
B. 11.5
C. 12
D. 10.5
Explanation:
Average of the first ‘n’ natural numbers = (n + 1)/2
We get (20 + 1)/2 = 10.5
A. 2dm
B. 6dm
C. 18dm
D. 72dm
A. if a < b
B. if a ≤ b
C. if the relationship between a and b cannot be established.
D. if a > b
Explanation:
I.(a – 3)(a – 4) = 0
=> a = 3, 4
II. (b – 2)(b – 1) = 0
=> b = 1, 2
=> a > b