A. 420
B. 515
C. 435
D. 518
A. Rs. 7500
B. Rs. 9000
C. Rs. 9500
D. Rs. 10,000
E. None of these
Explanation:
A:B:C = (20000 * 24) : (15000 * 24) : (20000 * 18) = 4:3:3
B’s = 25000 * 3/10 = Rs. 7500.
A. 35
B. 37
C. 42
D. 30
Explanation:
The number of liters in each can = HCF of 80, 144 and 368 = 16 liters.
Number of cans of Maaza = 80/16 = 5
Number of cans of Pepsi = 144/16 = 9
Number of cans of Sprite = 368/16 = 23
The total number of cans required = 5 + 9 + 23 = 37 cans.
A. 1/2
B. 16/19
C. 4/5
D. 17/20
Explanation:
n(S) = 20
n(Even no) = 10 = n(E)
n(Prime no) = 8 = n(P)
P(EᴜP) = 10/20 + 8/20 – 1/20 = 17/20
A. 8
B. 6
C. 4
D. 2
Explanation:
Let n erasers be available for a rupee
Reduced Price = (75/100 × 1) = Re ¾
¾ rupee fetch n erasers = 1 Rupee will fetch (n × 4/3) erasers
Therefore, 4n/3 = n +2 => 4n = 3n +6 => n =6
A. Rs.350
B. Rs.375
C. Rs. 380
D. Rs. 400
Explanation:
The principle is P.
P(1 +10/100)2 – P = 420
=> P = Rs.2000
S.I = Rs.(4000/100) = Rs.400
A. One
B. Zero
C. Three
D. Cannot be determined
Explanation:
We cannot predicted the number of dinners that the particular number has to host in one year.