What is the least number which when divided by 8, 12, 18 and 24 leaves the remainders 4, 8, 14 and 20 respectively?
A. 78
B. 68
C. 58
D. None
A. 78
B. 68
C. 58
D. None
A. Rs. 31
B. Rs. 32.10
C. Rs. 40.40
D. Rs. 64.10
Explanation:
S.I. = (1000 * 10 * 4)/100 = Rs. 400
C.I. = [1000 * (1 + 10/100)4 – 1000] = Rs. 464.10 Difference = (464.10 – 400) = Rs. 64.10
A. Rs.38750
B. Rs.38000
C. Rs.40000
D. Rs.42000
Explanation:
CP + CP/8 = 45000
CP = 40000
SP = 40000*(95/100) = 38000
A. 25%
B. 30%
C. 31.6%
D. 33.5%
Explanation:
100*(80/100)*(90/100)*(95/100) = 68.4
100 – 68.4 = 31.6
A. 10 2/5%
B. 12 3/5%
C. 11 1/5%
D. None of these
Explanation:
Let the required percentage be x%.
x% of 125 = 16 => x/100 * 125 = 16
=> x = 1600/125 = 64/5 = 12 4/5
A. 40
B. 50
C. 60
D. 80
Explanation:
Let the number be x. Then,
50% of x – 35% of x = 12
50/100 x – 35/100 x = 12
x = (12 * 100)/15 = 80.
A. Rs. 400
B. Rs. 450
C. Rs. 460
D. Rs. 480
Explanation:
Let the sum be Rs. P. Then,
[P(1 + 25/(2 * 100))2 – P] = 510
P[(9/8)2 – 1] = 510.
Sum = Rs. 1920
So, S.I. = (1920 * 25 * 2) / (2 * 100) = Rs. 480