Areas | Mathematics Mcqs

The largest size of bamboo that can be placed in a square of area 100 sq.meters is__________?

Byadmin July 14, 2019August 4, 2021

The largest size of bamboo that can be placed in a square of area 100 sq.meters is__________?

A. 10m
B. 14.14m
C. 20m
D. 25m

Arithmetic Mcqs | Average Mcqs | Basic Maths Mcqs | Mathematics Mcqs

The average age of a group of 10 persons was decreased by 3 years when one person, whose age was 42 years, was replaced by a new person. Find the age of the new person?

The average age of a group of 10 persons was decreased by 3 years when one person, whose age was 42 years, was replaced by a new person. Find the age of the new person?

A. 22
B. 24
C. 12
D. 8
Explanation:
Initial average age of the 10 persons be P.
Age of the new person Q.
Sum of the ages of the initial 10 persons = 10P
New average = (P-3) 10(P-3) = 10P – 42 + Q => Q = 12

Read More The average age of a group of 10 persons was decreased by 3 years when one person, whose age was 42 years, was replaced by a new person. Find the age of the new person?
Mathematics Mcqs | Probability

A box contains nine bulbs out of which 4 are defective. If four bulbs are chosen at random, find the probability that at least one bulb is good.

A box contains nine bulbs out of which 4 are defective. If four bulbs are chosen at random, find the probability that at least one bulb is good.

A. 6/63
B. 2/63
C. 125/126
D. 1/126
Explanation:
Required probability = 1 – 1/126 = 125/126

Read More A box contains nine bulbs out of which 4 are defective. If four bulbs are chosen at random, find the probability that at least one bulb is good.
Mathematics Mcqs | Simplification and Approximation

Jameel gets on the elevator at the 11th floor of a building and rides up at the rate of 57 floors per minute. At the same time, Nasir gets on an elevator at the 51st floor of the same building and rides down at the rate of 63 floors per minute. If they continue travelling at these rates, then at which floor will their paths cross?

Jameel gets on the elevator at the 11th floor of a building and rides up at the rate of 57 floors per minute. At the same time, Nasir gets on an elevator at the 51st floor of the same building and rides down at the rate of 63 floors per minute. If they continue travelling at these rates, then at which floor will their paths cross?

A. 19
B. 28
C. 30
D. 37

Read More Jameel gets on the elevator at the 11th floor of a building and rides up at the rate of 57 floors per minute. At the same time, Nasir gets on an elevator at the 51st floor of the same building and rides down at the rate of 63 floors per minute. If they continue travelling at these rates, then at which floor will their paths cross?
Mathematics Mcqs | Percentage Mcqs

Two-fifth of one-third of three-seventh of a number is 15. What is 40% of that number?

Two-fifth of one-third of three-seventh of a number is 15. What is 40% of that number?

A. 72
B. 84
C. 136
D. 140
E. None of these
Explanation:
Let the number be x. Then,
2/5 of 1/3 of 3/7 of
x = 15 => x = (15 * 5/3 * 3 * 5/2) = 525/2
40% of 525/2 = (40/100 * 525/2) = 105

Read More Two-fifth of one-third of three-seventh of a number is 15. What is 40% of that number?
Mathematics Mcqs | Simplification and Approximation

(815 / ?) / 100 * 28 * 3 – (815 * 14 * 6)/100 = 1680

(815 / ?) / 100 * 28 * 3 – (815 * 14 * 6)/100 = 1680

A. 2000
B. 3000
C. 4000
D. 6000
Explanation:
Let 815 + ? be k
=> 84k/100 – (815 * 84)/100 = 1680
=>84(k/100 – 815/100) = 1680
=> (k – 815)/100 = 20 => k = 2815
k = 815 + ? = 2815 => ? = 2000

Read More (815 / ?) / 100 * 28 * 3 – (815 * 14 * 6)/100 = 1680
Mathematics Mcqs | Problems on L.C.M and H.C.F

The wheels revolve round a common horizontal axis. They make 15, 20 and 48 revolutions in a minute respectively. Starting with a certain point on the circumference down wards. After what interval of time will they come together in the same position?

The wheels revolve round a common horizontal axis. They make 15, 20 and 48 revolutions in a minute respectively. Starting with a certain point on the circumference down wards. After what interval of time will they come together in the same position?

A. 1 min
B. 2 min
C. 3 min
D. None
Explanation:
Time for one revolution = 60/15 = 4
60/ 20 = 3
60/48 = 5/4
LCM of 4, 3, 5/4
LCM of Numerators/HCF of Denominators =
60/1 = 60

Read More The wheels revolve round a common horizontal axis. They make 15, 20 and 48 revolutions in a minute respectively. Starting with a certain point on the circumference down wards. After what interval of time will they come together in the same position?