The length of a rectangle is twice its breadth, if length is decreased by 5 cm and the breadth is increased by 5 cm. The length of the rectangle is_________?
A. 20 cm
B. 30 cm
C. 40 cm
D. 50 cm
A. 20 cm
B. 30 cm
C. 40 cm
D. 50 cm
A. Circle
B. Square
C. Equilateral Triangle
D. Both Triangle and Square
A. 9!/(2!)2 3!
B. 9!/(2!)3 3!
C. 9!/(2!)2 (3!)2
D. 5!/(2!)2 3!
Explanation:
n items of which p are alike of one kind, q alike of the other, r alike of another kind and the remaining are distinct can be arranged in a row in n!/p!q!r! ways.
The letter pattern ‘MESMERISE’ consists of 10 letters of which there are 2M’s, 3E’s, 2S’s and 1I and 1R.
Number of arrangements = 9!/(2!)2 3!
A. 10/7
B. 10
C. 10/11
D. 11/10
Explanation:
LCM of numerators = 10
HCF of denominators = 1
=> 10/1 = 10
A. 8: 1
B. 2√2 : 1
C. 2 : 1
D. None of these
Explanation:
Volumes be 8×3 and x3
2x and x respectively
Therefore, Ratio of their edges = 2 : 1
A. 1037.50
B. 1157.50
C. 103.75
D. 1038
Explanation:
12.5 + 10 1/4 of 100 ÷ 10% of 10
= 12.5 + 41/4 of 100 ÷ 10/100 of 10
= 12.5 + 41(25) ÷ 1 = 12.5 + 1025 = 1037.5
A. 120
B. 260
C. 240
D. 220
Explanation with best method.
5 Steps
1.Data:
Train station platform= 36Sec
Standing platform = 20Sec
Speed of train = 54km/hr
2.Required:
Length of platform= x=???
3.Formula:
X+length of train/Train station platform
4.Solution: first for terms
Speed = 54 ×1000m/3600sec = 15 m/Sec.
Length of the train = (15 m/Sec × 20Sec = 300 m.
Let the length of the platform be x metres.
Now, x + 300m /36Sec= 15 m/Sec
x+300m= 15m/Sec×36Sec
x + 300m = 540m
x= 540m-300m
x = 240 m.
5.Result:
Length of platform=x=240m